Your coworker was impressed with the efficiency you showed in the previous problem and would like to apply your methods to a pro
1 answer:
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Answer:
18 kJ
Explanation:
Given:
Initial volume of air = 0.05 m³
Initial pressure = 60 kPa
Final volume = 0.2 m³
Final pressure = 180 kPa
Now,
the Work done by air will be calculated as:
Work Done = Average pressure × Change in volume
thus,
Average pressure = = 120 kPa
and,
Change in volume = Final volume - Initial Volume = 0.2 - 0.05 = 0.15 m³
Therefore,
the work done = 120 × 0.15 = 18 kJ
<u>Explanation:</u>
Determine the weight of footing
Where is the weight of footing, γ is the unit weight of concrete, L is the length of footing is the width of footing, and D is the depth of footing
Substitute for γ in the equation
Therefore, the weight of the footing is 35.4 kN
Determine the initial vertical effective stress.
Here, is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.
Substitute for u in the equation
Therefore, the initial vertical stress is 36 kPa
Determine the vertical effective stress.
Here, is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.
Substitute in the equation.
Therefore, the vertical stress at a depth below the ground surface is
9 kPa
Determine the influence factor at the midpoint of soil layer,
Here is the influence factor at the midpoint of soil layer
is initial vertical stress,
is vertical effective stress, and
is bearing pressure
Substitute in the equation
Therefore the influence factor at the midpoint of the soil layer is 0.693