This question involves the concepts of power and current.
The power output of the motor is "10.08 hp".
<h3>Power Output</h3>
The power output of the motor can be found using the following formula:
P = ηVI
where,
- P = Power = ?
- η = efficiency = 90 % = 0.9
- I = current = 38 A
- V = potential difference = 220 V
Therefore,
P = (0.9)(38 A)(220 V)
P = 7524 watt
converting this to horsepower:
P = (7524 watt)(
)
P = 10.08 hp
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Answer:
The answer is below
Explanation:
Let A represent the first switch, B represent the second switch and C represent the bulb. Also, let 0 mean turned off and 1 mean turned on. Since when both switches are in the same position, the light is off. This can be represented by the following truth table:
A B C (output)
0 0 0
0 1 1
1 0 1
1 1 0
The logic circuit can be represented by:
C = A'B + AB'
The output (bulb) is on if the switches are at different positions; if the switches are at the same position, the output (bulb) is off. This is an XOR gate. The gate is represented in the diagram attached below.
The total present worth is $19,783.01
The present worth of a series of cash flow is the value of the cash flows in year 0 (today)
Cash flow in year 0 = 5330
Cash flow in year 1 = 0
Cash flow in year 2 = 0
Cash flow in year 3 = 13075 / (1.02)^3 = 12,320.86
Cash flow in year 4 = 2308 / (1.02)^4 = 2,132.24
Present worth = $19,783.01
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Answer:
Technician B
Explanation:
The brakes can lockup due to the following reasons
1) Overheating break systems
2) Use of wrong brake fluid
3) Broken or damaged drum brake backing plates, rotors, or calipers
4) A defective ABS part, or a defective parking mechanism or proportioning valve
5) Brake wheel cylinders, worn off
6) Misaligned power brake booster component