Once you know your basic operations addition<span>, </span>subtraction,multiplication<span>, </span>division <span>you will encounter story problems also known as word problems that require you to read a problem and decide which operation to perform in order to get the answer. There are key words here that often indicate which operation you will use. We will give you a list of them, but remember that for many problem</span><span>s </span><span>there may not be a key word and you’ll have to use your best judgment in order to figure out what to do. </span>
Step-by-step explanation:
Students Hours
52 8
X 6
So,
52×6=8×x
312=8x
312/8=x
39 Students Answer
Answer:
5
Step-by-step explanation:
We are asked to find the value of A. We know from the question that we need to have the sum of -3x and (A)x equal the third term of the original polynomial, which is 2x. written out in an equation, it looks like this.

We can simplify the equation if we add 3x to both sides, which then leaves us with this.

We can further simplify the equation by dividing both sides by x. This leaves us with our last equation for this problem.

Finally, we have our answer. We can also verify that this is a valid integer by multiplying our, now completed, quotient by the divisor and adding the remainder, which in this case, our remainder is 0, so we will not be including it in our operation.

If our calculations were all correct, the product of these polynomials should equal our dividend, verifying our integer is valid; lo' and behold, it is.

There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.