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mina [271]
3 years ago
6

Why there is no (not enough) gravity on a Moon?

Physics
2 answers:
Svetlanka [38]3 years ago
8 0

Hi


I would say it because the moon is too small and its gravity is not stronger enough to hold the heavy gases like dioxide and Carbone.


I hope that's help:)

11Alexandr11 [23.1K]3 years ago
7 0
There's plenty gravity on the moon.

The acceleration (strength) of gravity on the surface of any
planet, moon, asteroid, comet, etc. depends on the mass
and size of that body.

The Moon's mass is about 1/80 as much as the Earth's mass,
and its diameter is about  0.273 the size of Earth's diameter.

       (about 1/80) times (about 1/0.273²) = about  0.168

This says that the Moon's gravity should be about 0.168
as strong as the Earth's gravity.

The real number is  0.165 .  Not bad.
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Read 2 more answers
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
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Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

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\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

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