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Nitella [24]
3 years ago
15

Short wavelengths, from high-pitched sounds, cause displacement of the basilar membrane near the oval window. true false

Physics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

True

Explanation:

Short wavelengths, from high-pitched sounds, cause displacement of the basilar membrane near the oval window, is a True statement.

Stapes bones transmit movement to the oval windows. Stapes cause the round window membrane to move out. This turn allows the movement of fluid within the cochlea. This leads to motion of inner cochlear inner hair and thus hearing is possible.

Oksana_A [137]3 years ago
5 0

Answer:

True

Explanation:

Before explaining the reason let's first know some of the terminologies used in the question.

Cochlea:

Cochlea is the spiral cavity of the inner ear which transform sound in neural message.

Basilar membrane:

The basilar membrane is a stiff structural element within the cochlea of the inner ear which separates two liquid-filled tubes running along the coil of cochlea.

Oval Window:

It is a membrane around the cochlea.

Volume of sound is directly proportional to the amplitude of a sound wave.

While the frequency of sound is inversely proportion to the  wavelength of sound waves thus high pitch sound are produced by short wavelength and vice versa.

If the displacement of the basilar membrane is near to the oval window by a sound, then we can detect that sound, because sound waves stimulate the the basilar membrane and then sound waves are detected.  

The structure of the cochlea varies, so sound waves of different wavelengths stimulate different areas in the basilar membrane.

shorter the wavelength higher is the chance to stimulate basilar membrane.  

Increasing the pitch of sound (i.e. making the wavelength shorter) decreases the displacement of the basilar membrane to the oval window and thus we detect the sound waves.

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inserting the values

F_{1}=\frac{(9\times 10^{9})(2 \times 10^{-6})^{2}}{0.5^{2}}

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F_{2}=\frac{kQ^{2}}{r_{2}^{2}}

inserting the values

F_{2}=\frac{(9\times 10^{9})(2 \times 10^{-6})^{2}}{1^{2}}

F₂ = 0.036 N

Net force on the charge at the origin is given as

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from the diagram , direction of net force is towards left or negative x-direction.


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3 years ago
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Explanation:

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