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Nitella [24]
3 years ago
15

Short wavelengths, from high-pitched sounds, cause displacement of the basilar membrane near the oval window. true false

Physics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

True

Explanation:

Short wavelengths, from high-pitched sounds, cause displacement of the basilar membrane near the oval window, is a True statement.

Stapes bones transmit movement to the oval windows. Stapes cause the round window membrane to move out. This turn allows the movement of fluid within the cochlea. This leads to motion of inner cochlear inner hair and thus hearing is possible.

Oksana_A [137]3 years ago
5 0

Answer:

True

Explanation:

Before explaining the reason let's first know some of the terminologies used in the question.

Cochlea:

Cochlea is the spiral cavity of the inner ear which transform sound in neural message.

Basilar membrane:

The basilar membrane is a stiff structural element within the cochlea of the inner ear which separates two liquid-filled tubes running along the coil of cochlea.

Oval Window:

It is a membrane around the cochlea.

Volume of sound is directly proportional to the amplitude of a sound wave.

While the frequency of sound is inversely proportion to the  wavelength of sound waves thus high pitch sound are produced by short wavelength and vice versa.

If the displacement of the basilar membrane is near to the oval window by a sound, then we can detect that sound, because sound waves stimulate the the basilar membrane and then sound waves are detected.  

The structure of the cochlea varies, so sound waves of different wavelengths stimulate different areas in the basilar membrane.

shorter the wavelength higher is the chance to stimulate basilar membrane.  

Increasing the pitch of sound (i.e. making the wavelength shorter) decreases the displacement of the basilar membrane to the oval window and thus we detect the sound waves.

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Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0

example:  A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.

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8 0
3 years ago
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sattari [20]

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3 years ago
A 100g block lies on an inclined plane that makes an angle of 15 degrees with the horizontal. The coefficient of kinetic frictio
Fed [463]

Answer:

Mass that one should put in the container so that the 100 g block slides down the inclined plane at constant speed = 34.16 g

Explanation:

The vertical forces (with respect to the inclined plane) acting on the 100 g block include the component of the weight of the block in the direction vertical to the inclined plane and the normal reaction of the plane on the block.

And sum of upward forces = sum of downward forces.

N = mg cos θ

m = 100 g = 0.10 kg

g = acceleration due to gravity = 9.8 m/s²

θ = 15°

N = (0.1×9.8×cos 15°) = 0.946582 N

The horizontal forces (With respect to the inclined plane) include the frictional force (acting upwards for the inclined plane, opposite to the intended direction of motion), the Tension in the rope (acting downwards, away from the 100 g block) and the horizontal component (with respect to the inclined plane) of the weight of the block, F, (also acting downards).

For the body to slide down the inclined plane at constant speed, the downward sloping forces must balance the frictional force, that is, there will be no acceleration.

Frictional force = Tension + F

Frictional force = μN

where μ = coefficient of kinetic friction = 0.60

N = normal reaction = 0.9466 N

Frictional force = Fr = (0.60 × 0.9466) = 0.56796 N = 0.568 N

The horizontal component (with respect to the inclined plane) of the weight of the block (also acting downards) = mg sin θ

F = (0.10 × 9.8 × sin 15°) = 0.253624 N

Tension in the rope = T = ?

Fr = F + T

T = Fr - F = 0.568 - 0.253624 = 0.314376 N = 0.3144 N

But the balance on the rope now has the total weight on the container (weight of container + weight on the container) to be equal to 2T.

2T = mg

2 × 0.3144 = 9.8m

m = 0.06416 kg = 64.16 g.

Mass of the container = 30 g

So, mass that one should put in the container so that the 100 g block slides down the inclined plane at constant speed = 64.16 - 30 = 34.16 g

Hope this Helps!!!

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