How does the nucleus of an atom change when it emits an alpha or beta particle?

1 answer:

5 0

First of all, an alpha particle consists of two protons and two neutrons (similar to a Helium atom). When an atom emits an alpha particle, its nucleus loses two protons and two neutrons. And its total mass decreases by 4 atomic mass units.(As mass of a proton or a neutron is 1 amu)

There are two kinds of beta emissions (or particles) positron or electron.

When an atom emits a ${ \beta }^{ + }$ (positron) particle, actually one if its protons releases the particle. Since a positron's charge is positive, when the atom releases a positron it loses its positive charge and turns into a neutron.

When an atom emits a ${ \beta }^{ - }$ (electron) particle, one of its neutrons releases a ${ \beta }^{ - }$ (electron). And since an electron's charge is negative (-) the neutron loses its negative charge (since neutron's electrical charge is neutral) and turns into a proton.

This is simply explained ^

There are some other details but this should be enough :)

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An object thrown vertically upward from the surface of a celestial body at a velocity of 36 m/s reaches a height of sequalsminu

Anarel [89]

Answer:

v = -1.8t+36

20 seconds

360 m

40 seconds

36 m/s

The object speed will increase when it is coming down from its highest height.

Explanation:

$s=-0.9t^2+36t$

Differentiating with respect to time we get

$\frac{ds}{dt}=-1.8t+36\\\Rightarrow v=-1.8t+36$

a) Velocity of the object after t seconds is v = -1.8t+36

At the highest point v will be 0

$0=-1.8t+36\\\Rightarrow t=\frac{-36}{-1.8}\\\Rightarrow t=20\ s$

b) The object will reach the highest point after 20 seconds

$s=-0.9t^2+36t\\\Rightarrow s=-0.9\times 20^2+36\times 20\\\Rightarrow s=360\ m$

c) Highest point the object will reach is 360 m

$s=-0.9t^2+36t\\\Rightarrow 360=-0.9t^2+36t\\\Rightarrow -0.9t^2+36t-360=0\\\Rightarrow -9t^2+360t-3600=0$

$\frac{-360\pm \sqrt{0}}{2\left(-9\right)}\\\Rightarrow t=20\ s$

d) Time taken to strike the ground would be 20+20 = 40 seconds

$[tex]v=u+at\\\Rightarrow v=0+0.9\times 2\times 20\\\Rightarrow v=36\ m/s$

Acceleration will be taken as positive because the object is going down. Hence, the sign changes. 2 is multiplied because the expression is given in the form of $s=ut+\frac{1}{2}at^2$

e) The velocity with which the object strikes the ground will be 36 m/s

f) The speed will increase when the object has gone up and for 20 seconds and falls down for 20 seconds. The object speed will increase when it is coming down from its highest height.

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3 years ago

A 100 kg astronaut weighs 980N on Earth. The same astronaut weighs only 162.2 N on the Moon. Which of the following statements e

andrey2020 [161]

Answer:

100

Explanation:

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2 years ago

What is the measuring devices of a mass

erik [133]

The measuring devices for mass is scales and Balances