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Leviafan [203]
3 years ago
10

Write Balance chemical reaction for preparation of chlorine with or without application heat​

Chemistry
1 answer:
suter [353]3 years ago
3 0

Answer:

2KMnO4(aq) + 16HCl(aq) ------> 2MnCl2(aq) + 2KCl(aq) + 8H2O(l) + 5Cl2(g)

Explanation:

Chlorine is a diatomic halogen gas known for its greenish-yellow colour. It has a pungent smell and is only moderately soluble in water.

It is a very reactive gas and is never found in free state in nature.

Chlorine can be prepared in the laboratory by oxidation of hydrochloric acid using KMnO4 as follows;

2KMnO4(aq) + 16HCl(aq) ------> 2MnCl2(aq) + 2KCl(aq) + 8H2O(l) + 5Cl2(g)

The set up does not need to be heated.

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Atoms form chemical bonds to satisfy the rule and to become .
soldi70 [24.7K]

Answer: Atoms form chemical bonds to satisfy the<u> Octet</u> rule and to become <u>stable.</u>

Explanation:

The tendency of atoms to attempt to get a noble gas configuration that is eight valence electrons is said to be octet rule.  This is done to attain noble gas configuration and stability.

In order to attain stability the atoms tends to have eight electrons in its valence shell which can be obtained by either by sharing of electrons or complete transfer of electrons.

For example : As we know that the sodium has one valence electron, so if giving it up then the result in the same electron configuration as the neon and chlorine has seven valence electrons, so if it takes one it will have eight and the result in the same electronic configuration as the argon which is stable.

4 0
4 years ago
A car traveling at 30 m/s comes to a stop in 5 seconds. What is the acceleration of this car?
aliina [53]

Answer:

6m/s brainliest?

Explanation:

5 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Consider both 5-methyl-1,3-cyclopentadiene (A) and 7-methyl-1,3,5-cycloheptatriene (B). Which label
LuckyWell [14K]
I don’t have a picture but I can describe it to you.

The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.

The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.

Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.

Hope this helps!
6 0
3 years ago
The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hert
Fed [463]

Answer:

6.56×10¹⁴ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength = 457 nm

Frequency =?

Next, we shall convert 457 nm to metre (m). This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

457 nm = 457 nm × 1×10¯⁹ m / 1 nm

457 nm = 4.57×10¯⁷ m

Thus, 457 nm is equivalent to 4.57×10¯⁷ m

Finally, we shall determine the frequency of the blue light as follow:

Wavelength = 4.57×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency =?

Velocity = wavelength x frequency

3×10⁸ = 4.57×10¯⁷ × frequency

Divide both side by 4.57×10¯⁷

frequency = 3×10⁸ / 4.57×10¯⁷

frequency = 6.56×10¹⁴ Hz

Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz

6 0
3 years ago
What happens when you heat an air filled sealed can ?
Mandarinka [93]
The pressure increases and would explode
8 0
3 years ago
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