Some chemical changes can be reactive through another chemical change?
It is used to separate an insoluble solute from a liquid.
It is normally filtered by using filter paper, the liquid that passes through the paper is called filtrate, meanwhile the insoluble particles and a bit liquid left on the filter paper is called residue.
We can also separate insoluble solute from liquid by decantation.
Answer:
5.42
Explanation:
Step 1: Consider the dissociation of NH₄Br
NH₄Br(aq) ⇒ NH₄⁺(aq) + Br⁻(aq)
Br⁻ is the conjugate base of HBr, a strong acid, so it doesn´t react with water. NH₄⁺ is the conjugate acid of NH₃, so it does react with water.
Step 2: Consider the acid reaction of NH₄⁺
NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)
Step 3: calculate the acid dissociation constant for NH₄⁺
We will use the following expression.
Step 4: Calculate the concentration of H₃O⁺
We will use the following expression.
Step 5: Calculate the pH
We will use the following expression.
Answer:
C. The lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, all of which have the same spin, in degenerate orbitals.
Explanation:
The Hund's rule is used to place the electrons in the orbitals is it states that:
1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied;
2. All of the electrons in singly occupied orbitals have the same spin.
So, the electrons first seek to fill the orbitals with the same energy (degenerate orbitals) before paring with electrons in a half-filled orbital. Orbitals doubly occupied have greater energy, so the lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, and for the second statement, they have the same spin.
The other alternatives are correct, but they're not observed by the Hund's rule.
The resulting pressure is 3.093 atm
<u><em>calculation</em></u>
The resulting pressure is calculated using the combined gas equation
That is P₁V₁/T₁ =P₂V₂/T₂ where,
P₁=0.956 atm
V₁=4.95 L
T₁=22.8 c in to kelvin= 22.8 +273 =295.8 k
P₂=? atm
V₂=1.75 L
T₂=65.3 c into kelvin = 65.3 +273 =338.3 K
make P₂ the subject of the formula by multiplying both side of the formula by T₂/V₂
P₂ =T₂P₁V₁ / V₂T₁
P₂ = [(338.3 k x 0.956 atm x 4.95 L) / ( 1.75 L x 295.8 K)] =3.093 atm