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3 years ago

If 2x-3y+5-(x-3y)=11-2x, what is the value of x?

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

4 0

Answer:

$x=2$

Step-by-step explanation:

$2x-3y+5-\left(x-3y\right)=11-2x$

Remove brackets and flip the sign in the brackets:

$2x-3y+5-x+3y=11-2x$

Group the similar terms together:

$-3y+3y+2x-x+5=11-2x$

Add/subtract the terms:

$x+5=11-2x$

Subtract 5 from both sides:

$x+5-5=11-2x-5$

$x=-2x+6$

Add 2x to both sides:

$x+2x=-2x+6+2x$

$3x=6$

Divide both sides by 3:

$\frac{3x}{3}=\frac{6}{3}$

$x=2$

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mixer [17]

Answer:

25. Not a solution

26. Yes a solution

27. y= 2/3 x

28. y=3x+16

Step-by-step explanation:

25. The solution to a linear equation is the point (x,y). To find if an (x,y) is a solution, substitute it into the equation and see if it works.

y=4x-4 and (8,3)

3=4(8)-4

3=32-4

3=28

False

Not a solution.

26. Repeat 25 to solve 26 with y=5x-5 and (0,-5)

y=5x-5 and (0,-5)

-5=5(0)-5

-5=0-5

-5=-5

True

Yes a solution.

27. This line crosses through the origin is proportional and therefore has the form y=mx. It also has a gentle slant meaning that is less than 1/2 and goes in a positive direction. This means it is y=2/3 x.

28. Use inverse operations to rearrange the equation.

y-3x=16

y=16+3x

y=3x+16

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3 years ago

Select all of the choices that are equal to (-5) - (-12) -7 7 (-5)+12 (-5)+(-12)

Roman55 [17]

Answer:

the awnser is. (-5) + (-12)

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3 years ago

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Find the length of a side of a square if its área is 4/25 cm2

USPshnik [31]

Answer:

2/5cm or 0.4cm

Step-by-step explanation:

Area of square = $Side^{2}$

Thus, Side = $\sqrt{Area}$

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3 years ago

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Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

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On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

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3 years ago

Solve −4 = −(−k − 86)+10

kvasek [131]

K= 100

You use distributive property

Step 1: −(−k)−1(−86)+10=−4

Step 2: k−1(−86)+10=−4

Step 3: k+86+10=−4

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Step 5: k=−96−4

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