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Furkat [3]
3 years ago
5

What are the four components of a controlled experiment?. A. opinions, independent variable, constant, control. B. data that mat

ches previous research, opinions, variables, control. C. independent variable, dependent variable, control, constant. D. data that supports hypothesis, independent variable, constant, control.
Physics
1 answer:
kherson [118]3 years ago
3 0
I believe the correct answer among the choices listed is option C. The four components of a controlled experiment are the  independent variable, dependent variable, control, constant. A controlled experiment is a test where a researcher vary one variable at a time.<span>
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Helpp!!! Will mark brainlst
masya89 [10]

Answer:

i dont know

Explanation:

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5 0
3 years ago
A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block
gayaneshka [121]

The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

  • Mass of first block; m_1 = 5.0kg
  • Mass of second block, m_2 =10kg
  • Tension on first rope; T_1 =\ ?
  • Tension on second rope; T_2 =\ ?

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

Therefore, the tension in the second rope is 98 Newton

Learn More, brainly.com/question/18288215

4 0
2 years ago
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Hello there, Goodmorning and God Bless...Here is your answer to your following question:

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2 years ago
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Consider a roller coaster begins 15m above the ground. If the cart has a mass of 75kg, what is the velocity of the cart halfway
SashulF [63]

Answer:

v = 12.12 m/s

Explanation:

Given that,

The mass of the cart, m = 75 kg

The roller coaster begins 15 m above the ground.

We need to find the velocity of the cart halfway to the ground. Let the velocity be v. Using the conservation of energy at this position, h = 15/2 = 7.5 m

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 7.5} \\\\v=12.12\ m/s

So, the velocity of the cart is 12.12 m/s.

7 0
3 years ago
Wind tends to move from<br> pressure areas.<br> low, high<br> high, high<br> low, low<br> high, low
andrew-mc [135]

Answer:

high, low

Explanation:

  • Energy always flows from a higher level to a lower level.
  • It is analogous to the waterfall where waterfalls from a higher level to a lower level.
  • So in the case of the pressure of the gas, when there are any numbers of molecules in a given volume of space. The gas is said to be at high pressure.
  • When there are fewer molecules in the given volume. The gas is said to be at lower pressure.
  • Due to a large number of atoms, the high-pressure gas exerts more force on the container than the force exerted by the low-pressure gas.
  • If a hose is connected between these two containers, gas rushes from high pressure to the low pressure. Since the force exerted by the high-pressure gas is greater than that of low-pressure gas.

So, the wind tends to move from high-pressure areas to low pressure.

3 0
2 years ago
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