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Harman [31]
4 years ago
11

A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration ?

Physics
1 answer:
Nataliya [291]4 years ago
5 0

Answer:

-3m {s}^{-2}

Explanation:

The initial velocity, u, of the car=15m/s

The final velocity, v, of the car =0m/s

Time, t, taken for the car to come to a stop=5s

Acceleration is calculated by,

a= \frac{v - u}{t}

By substitution,

a= \frac{0- 15}{5}

a= \frac{- 15}{5}

a = -3 {ms}^{ - 2}

The negative sign implies that the car has decelerated.

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Which force can affect an object without direct physical contact?
denis-greek [22]
Gravity affet everything and it touches nothing.
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8 0
4 years ago
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A roller-skate with a mass of 10kg has a force of 12N exerted on it. At what rate did the skate accelerate?
nataly862011 [7]

Answer:

1.2ms⁻²

Explanation:

F = ma

12 = 10*a

12/10 = a

6/5 ms⁻² = a   or 1.2 ms⁻² = a

6 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
Tema [17]

Answer:

841.5 Hz

Explanation:

Given

y = 50 cm = 0.5 m

d = 5.00 m

L = 12.0 m away from the wall

v = speed of sound = 343 m/s

The image of the scenario is presented in the attached image.

When destructive interference is being experienced from 50 cm (0.5 m) parallel to the wall, the path difference between the distance of the two speakers from the observer is equal to half of the wavelength of the wave.

Let the distance from speaker one to the observer's new position be d₁

And the distance from the speaker two to the observer's new position be d₂

(λ/2) = |d₁ - d₂|

d₁ = √(12² + 3²) = 12.3693 m

d₂ = √(12² + 2²) = 12.1655 m

|d₁ - d₂| = 0.2038 m

(λ/2) = |d₁ - d₂| = 0.2038

λ = 0.4076 m

For waves, the velocity (v), frequency (f) and wavelength (λ) are related thus

v = fλ

f = (v/λ) = (343/0.4076) = 841.5 Hz

Hope this Helps!!!

7 0
4 years ago
Read 2 more answers
ANSWER QUICK PLS
vichka [17]

Answer:

what was the answer? Was it 0.98?

7 0
3 years ago
Read 2 more answers
What is the net force needed to accelerate a 5 kg object at 3 m/s2? Suppose that in this situation you discovered that there is
Rudik [331]

The Force need to accelerate the object is by 3 m/s² is 15 N.  Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

<h3>Force:</h3>

This can be defined as the product of the mass and the acceleration of a body. The S.I unit of force is kgm/s or Newton(N)

To calculate the force needed to accelerate a mass of 5 kg object at 3 m/s² we use the formula below.

Formula:

  • F = ma........ equation 1

Where:

  • F = Net force needed to accelerate the object
  • m = mass of the object
  • a = acceleration of the object

From the question,

Given:

  • m = 5 kg
  • a = 3 m/s²

Substitute these values into equation 1

  • F = 5(3)
  • F = 15 N

Suppose a frictional force of 5 N acts on the motion, The force applied is

  • F = F'+ma............ Equation 2

Where:

  • F = Frictional force = 5N

Substitute into equation 2

  • F = 5(3)+5
  • F' = 15+5
  • F = 20 N.

Hence, The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

Learn more about force here: brainly.com/question/12970081

4 0
3 years ago
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