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Harman [31]
3 years ago
11

A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration ?

Physics
1 answer:
Nataliya [291]3 years ago
5 0

Answer:

-3m {s}^{-2}

Explanation:

The initial velocity, u, of the car=15m/s

The final velocity, v, of the car =0m/s

Time, t, taken for the car to come to a stop=5s

Acceleration is calculated by,

a= \frac{v - u}{t}

By substitution,

a= \frac{0- 15}{5}

a= \frac{- 15}{5}

a = -3 {ms}^{ - 2}

The negative sign implies that the car has decelerated.

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\nabla  \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z

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