here we are told that
number of dolls sold varies directly with advertising costs
number of dolls varies inversely with price of a doll
so initially
1800 dolls sold when advertising costs were $ 34 000
and price of a doll was $ 25
next they increased the advertising costs to $ 42 000
as we know number of dolls sold varies directly with advertising costs
so here when the advertising costs increase the number of dolls sold too should increases as its directly proportional relationship
we arent told that the price of a doll is changed so there's no effect on the number of dolls sold due to changes in price of a doll
only effect on number of dolls sold is due to increase in advertising costs
increase in advertising cost leads to increase in number of dolls sold
from the given options, only in one option the number of dolls sold are more than 1800 dolls. option is C with 2224 dolls
therefore correct answer is C. 2224 dolls
Answer:
1. x = -3
2. x = 4/3
3. x = 698/77
Step-by-step explanation:
4+2x=-2
-4 -4
2x= -6
/2 /2
x=-3
You have to get x alone on one side. Search up on yt "How to solve for x on two sides."
Let the original price of the sweater be = X
Then the amount Jerome pays for the sweater after 20% discount = X - (20X/100)
= X - 0.2X
= 0.8X
Now on this price the 8.25% tax needs to be added to get to the amount actually paid by Jerome.
So,
0.8X + [(8.25/100) * (0.8X) = 25.1
This is the equation from which the actual price of the sweater bought by Jerome can be determined.
So
0.8X + [(.0825) * ( 0.8X) = 25.1
0.8X + 0.066X = 25.1
0.866X = 25.1
X = 25.1/0.866
= 28.98
So the actual price of the sweater is $28.98.
Answer:
Minnie and Amanda have the same amount of posters.
Step-by-step explanation:
Add 16 and 25 posters and Minnie will have a total of 41 posters.
Add 25 and 16 posters and Amanda will have a total of 41 posters.
Each have the same amount of posters regardless if they are new or old.
Answer:
A at the top of the building, and an endpoint C at the front door. The building is 43 stories tall. So we know that the length of AC 43 Chris works at point
