Question

Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a principal quantum number of 1.

Answer 1

Answer:

L_max= 0

Explanation:

The formula for magnitude of maximum orbital angular momentum is given by

$L_{max}= \sqrt{l(l+1)\bar{h}}$

l= orbital quantum number

l= n-1

n= shell number or principal quantum number

for n=1 , l=0

therefore, $L_{max}= \sqrt{0(0+1)\bar{h}}$

L_max= 0