The volume occupied by the argon gas is, 1.44 L
Explanation :
To calculate the volume of argon gas we are using ideal gas equation:
where,
P = pressure of argon gas = 1528 torr = 2.010 atm
Conversion used : (1 atm = 760 torr)
V = volume of argon gas = ?
T = temperature of argon gas = 
R = gas constant = 0.0821 L.atm/mole.K
w = mass of argon gas = 4.24 g
M = molar mass of argon gas = 39.95 g/mole
Now put all the given values in the ideal gas equation, we get:
Therefore, the volume of occupied by argon gas is 1.44 L
Explanation:
I haven't studied this in quite a long time but I will try my best to answer your question.
Gravity is a force that pulls things towards it and everything has gravity. The larger an object the stronger it's force of gravity and the more it pulls objects towards it. In our solar system the Sun is the largest object (by far) and therefore has the highest gravity. This means that the planets orbit the sun since the gravity of the sun is pulling the planets towards it. This stops planets from flying to outer space.
The thing that stops the planets from crashing into the sun is that they are travelling too fast. The planets are trying to travel in a straight direction, but the gravity and their speed in another direction kind of counteract and create a "medium" I guess you could call it, meaning the planet just orbits the sun.
when the metal is lost heat and the calorimeter of water is gained the heat
and when the heat lost = the heat gained so,
(M*C*ΔT)m = (M*C*ΔT)w
when Mm= mass of the metal = 30 g
Δ Tm = (80-25) = 55 °C
and Mw = mass of water = 100 g
Cw is the specific heat of water = 4.181 J/g.°C
ΔTw = (25-20) = 5 °C
so by substitution:
∴ 30* Cm*55 = 100 * 4.181 * 5
∴Cm (specific heat of metal) = (100*4.181*5)/(30*55)
∴C of metal = 1.267 J/g.°C
I think the correct answer would be <span>charged and insulated wire wrapped around a piece of iron. The charge in the wire would make magnetic fields through the aid of the magnetic properties of iron. Hope this helps. Have a nice day.</span>
