1. What is the pull that all objects exert on each other?

Physics

2 answers:

alukav5142 [94]2 years ago

6 0

Answer:

1. gravitational pull

2. force

Explanation:

Lemur [1.5K]2 years ago

3 0

Number one 1.

The downward pull on the object is due to gravity. is the force that objects exert on each other because of their masses. You are familiar with the force of gravity between Earth and objects on Earth. Gravity is present not only between objects and Earth, however.

Number two 2

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.

You might be interested in

An object on the surface of the earth has a force of gravity of 682 N. What is the objects mass?

valina [46]

The object's mass is around 69.592 kg

F=mg

5 0

2 years ago

How would you describe the appearance of the substance after the phase change?

Leona [35]

Answer:

Substances can change phase—often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous. The process of a solid becoming a liquid is called melting.

4 0

3 years ago

Help this was due yesterday...

insens350 [35]

Answer:

Concept: Periodic Trends

So we have Li and we have C
Li has is lower in the periodic table and as you progress from s group to p group and eventually d group, the traction and ability to attract electrons increases.
Hence option D

3 0

2 years ago

Read 2 more answers

The drag on a pitched baseball can be surprisingly large. Suppose a 145 g baseball with a diameter of 7.4 cm has an initial spee

kupik [55]

Answer:

<h2>Part A)</h2><h2>Acceleration of the ball is 10.1 m/s/s</h2><h2>Part B)</h2><h2>the final speed of the ball is given as</h2><h2> $v_f = 35.3 m/s$ </h2>

Explanation:

Part a)

As we know that drag force is given as

$F = \frac{C_d \rho A v^2}{2}$