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Karolina [17]
2 years ago
9

what happens when the gas produced by heating chloroform with silver powder is passed into Ammoniacal silver nitrate solution​

Chemistry
2 answers:
Butoxors [25]2 years ago
3 0

Explanation:

Chloroform and silver powder react with each other and exchange the ions with each other to form acetylene molecules which are also called ethyne and silver chloride. The molecule C2H2is called acetylene which is a colourless gas with no odour.

Firlakuza [10]2 years ago
3 0

Answer:

2CHCl3+6Ag−→ΔC2H2+6AgCl

Note: The Ag powder is synthesized by reducing silver nitrate with glycerol and here glycerol acts as the solvent for the reaction. The above given reaction can be proceeded with tribromomethane (bromoform) or triiodomethane (iodoform) since the structure of iodoform and bromoform resembles chloroform.

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
How many coppers of each atom in the products
yarga [219]

Answer:

Explanation:

moler mass of Cu is 63.546 g/mol. Since 63.546 g of copper has 6.022 x 10 power(23) atoms (Avogadro's number). = 9.5 x 10(power)21 atoms of copper.

6 0
2 years ago
Give two reasons why scientists create models to study atoms.
mariarad [96]
IT will be easy to know how chemical reactions occur
It will helps to know the fundamental particles of an atom
4 0
3 years ago
Some kayakers coat the bottom of their kayaks with wax to make them more slippery. Kayakers wax their boats to
Sindrei [870]
The answer is : C. reduce their input force
they put wax on their kayak to make their boat cut smoothly through the water, which make it able to obtain further distance with less input force, which will increase it's overall speed 
8 0
3 years ago
Read 2 more answers
How many core electrons are in a ground state atom of selenium?
Harman [31]
Electrons in an atom can be classified as core electrons and valence electrons. Valence electrons are those electrons which are present in valence shell and participates in bond formation. While, Core electrons are all remaining electrons which are not present in valence shell, hence not take part in bonding.

Atomic number of Selenium (Se) is 34 hence it has 34 electrons with following electronic configuration;

                          1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴

From electronic configuration it is found that the valence shell is 4, and the number of electrons present in valence shell are 6. So, 

             Core Electrons  =  Total Electrons - Valence Electrons

             Core Electrons  =  34 - 6

             Core Electrons  =  28

Result:
          There are 28 core electrons in Selenium.
3 0
3 years ago
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