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3 years ago

Is often mistakenly regarded as being based on science

1 answer:

5 0

The question is asking to state the term that is often mistakenly regarded as being base on science and base on my research and further analysis, I would say that the answer would be a Pseudoscience. I hope you are satisfied with my answer and feel free to ask for more if you have question

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How many moles of calcium are there in 5.74 x 1022 atoms of calcium?

igor_vitrenko [27]

Answer:

0.095 moles of Calcium is there in 5.74 x 1022 atoms of calcium.

Explanation:

As we know, 6.023*10^23 atoms of an element is equal to its atomic weight.

And, 6.023*10^23 atoms of an element is also equal to 1 mole of the element.

We have,

6.023*10^23 atoms of element calcium equals to 1 mole of Calcium
5.74*10^22 atoms of element calcium equals to

(1/(6.023*10^.23)) * 5.74*10^22 moles of calcium

Therefore,

5.74 x 1022 atoms of calcium= 0.095 moles of calcium.

6 0

3 years ago

How many liters of a 1.5 M solution can you make if you have .50 mol of KCl?

vaieri [72.5K]

Answer:

The answer to your question is 0.33 liters

Explanation:

Data

Volume = ?

Molarity = 1.5 M

number of moles = 0.5

Formula

$Molarity = \frac{number of moles }{volume}$

Solve for V

$Volume = \frac{number of moles}{molarity}$

Substitution

$Volume = \frac{0.5}{1.5}$

Simplification and result

Volume = 0.33 l

7 0

3 years ago

In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0

sp2606 [1]

Answer:

The value of $K_p$ for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = $p^o_{H_2O}=15.0 Torr$

Partial pressure of hydrogen gas at equilibrium = $p^o_{H_2}=?$

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

$P=p^o_{H_2O}+p^o_{H_2}$

$p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr$

$3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)$

The expression of $K_p$ is given by:

$K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}$

$K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066$

The value of $K_p$ for this reaction at 1200 K is 4.066.

6 0

3 years ago

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2

Alexxandr [17]

Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
the number of the mol solute

$22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L


$

$3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} 

$

$Molarity= \frac{0.178 mol}{L} , 

or 0.178 M
$

3 0

3 years ago

What specific electrophile does benzene attack when it undergoes nitration??

Deffense [45]

The reaction is as follows:
C6H6 + HNO3 + H2SO4 ------------> C6H5NO2 + H2O
(BENZENE) (NITRIC ACID)(CATALYST)
NO2(+) is the electrophile that acctacks on the benzene ring in nitration process.

7 0

3 years ago