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irinina [24]
4 years ago
10

Is often mistakenly regarded as being based on science

Chemistry
1 answer:
Alex777 [14]4 years ago
5 0
The question is asking to state the term that is often mistakenly regarded as being base on science and base on my research and further analysis, I would say that the answer would be a Pseudoscience. I hope you are satisfied with my answer and feel free to ask for more if you have question  
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Which statement describes a similarity between conductors and insulators?
Ivanshal [37]

Answer:

They can both be used in an electric circuit.

Explanation:

Though conductors and insulators are very different from each other but still they have a similarity that "they can both be used in an electric circuit".

Conductors are the material that allows electricity to flow and insulators have high resistance and do not allow electricity to flow.

Both conductors and insulators are used in an electric circuit as conductor is used in wires, batteries and bulb to flow current while insulators are used in insulation of wire, switches, plugs and etc. Combination of them makes the circuit shock free.

Hence, the correct answer is "They can both be used in an electric circuit."

4 0
3 years ago
2SnO2 + 4H2
Rainbow [258]

Answer:

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7 0
3 years ago
What is the constant parameters of pressure and volume? The relationship between the two? Are they directly proportional or inve
OverLord2011 [107]
Now I'm just going to assume you mean Charles law. So when working with gases, there are 4 properties: pressure, volume, temp, and quantity. The simple gas laws deal with 2, while leaving the other 2 constant. If Charles' Law changes temp and volume, what 2 stay constant? Pressure and quantity
6 0
3 years ago
List the types of friction in order from weakest to strongest
e-lub [12.9K]
Static Friction, Sliding Friction, Rolling Friction, and finally Fluid Friction.
5 0
4 years ago
What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
3 years ago
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