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3 years ago

Highly liquid lava forms wide, shield-like mountains. True False

Chemistry

1 answer:

timurjin [86]3 years ago

5 0

This answer is True :)

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A 850.0 mL cylinder containing B2H6 at a pressure of 0.900 atm is connected by a valve to 1000 mL cylinder containing C6H6 at 60

8_murik_8 [283]

Answer:

The partial pressure of $C_6H_6$ when the valve is opened is 328.6 Torr.

Explanation:

Initial pressure of the $C_6H_6=P_1=608.0 Torr$

Initial volume of the $C_6H_6=V_1=1000 mL$

After opening the valve :

Final pressure or partail pressure of the $C_6H_6=P_2$

Final volume of the $C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL$

$P_1V_1=P_2V_2$ ( Boyle's law)

$P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr$

The partial pressure of $C_6H_6$ when the valve is opened is 328.6 Torr.

4 0

3 years ago

How are tides created on earth?

N76 [4]

The gravitational interaction between the earth and the moon

4 0

3 years ago

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If predators A and B prey upon the same species and predator A is eliminated, the population of predator B will likely _________

trasher [3.6K]

Answer: B. Increase because there will be more resources for the remaining predators

5 0

3 years ago

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If the mass of a material is 75 grams and the volume of the material is 16 cm3, what would the density of the material be?

qwelly [4]

P=75/16=4.6875 g/cm³

7 0

4 years ago

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What is the molarity of SO4^2- in a solution prepared by mixing 2.17 g of alum, KAl(SO4)2•12H2O, with 175 mL of water? The molec

vodka [1.7K]

<u>Answer:</u> The concentration of sulfate ions in the solution is 0.0522 M

<u>Explanation:</u>

To calculate the the molarity of solution:, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of alum = 2.17 g

Molar mass of alum = 478.39 g/mol

Volume of solution = 175 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{2.17\times 1000}{474.39\times 175}\\\\\text{Molarity of solution}=0.0261M$

The chemical equation for the ionization of alum follows:

$KAl(SO_4)_2.12H_2O\rightarrow K^++Al^{3+}+2SO_4^{2-}+12H_2O$

1 mole of alum produces 1 mole of potassium ions, 1 mole of aluminium ions, 2 moles of sulfate ions and 12 moles of water

So, concentration of sulfate ions = $(2\times 0.0261)=0.0522M$

Hence, the concentration of sulfate ions in the solution is 0.0522 M

4 0

3 years ago