The balanced chemical reaction is:
C4H10 + 5O2 = 4CO2 + 2H2O
We are given the amount of butane to be used in the reaction. This will be the starting point of the calculations.
2.50 g C4H10 ( 1 mol C4H10 / 58.14 g C4H10) ( 4 mol CO2 / 1 mol C4H10 ) = 0.21 mol CO2
V = nRT / P = 0.21 mol CO2 (0.08206 atm L/mol K) 320.15 K / 1.04 atm = 5.30 L CO2
Generally (but far from universally), the elements within a group have similar characteristics. Antimony, nitrogen, and arsenic are all part of the same group as phosphorous (the pnictogens, or group 5A). Oxygen is not in this group, but rather in an adjacent group (the chalcogens, or group 6A). Thus, the answer here should be oxygen.
That said, there can be very significant differences in characteristics among the elements within a group, and that is certainly the case here. For example, free nitrogen exists predominantly as a molecular gas (N₂) and makes up about 78% of the atmosphere we breathe. Elemental arsenic (As), while in the same group as nitrogen, is naturally found in the solid state and is poisonous to humans (arsenic is sometimes included among the toxic heavy metals, although it’s technically a metalloid).
<h3>
Answer:</h3>
825 mL
<h3>
Explanation:</h3>
<u>We are given;</u>
- Molarity of HCl is 0.200 M
- Mass of CaCO₃ is 8.25 g
- The equation of the reaction as;
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
We are required to calculate the volume of the Acid that reacted.
<h3>Step 1: Determine the moles of CaCO₃ that reacted;</h3>
We know that;
Moles = Mass ÷ molar mass
Molar mass CaCO₃ is 100.1 g/mol
Therefore;
Moles of CaCO₃ = 8.25 g ÷ 100.1 g/mol
= 0.0824 moles
<h3>Step 2: Determine the moles of HCl that reacted;</h3>
From the reaction, 1 mole of CaCO₃ reacts with 2 moles of HCl
Therefore;
Moles of HCl = Moles of CaCO₃ × 2
= 0.0824 moles × 2
= 0.1648 moles
= 0.165 moles
<h3>Step 3: Determine the volume of HCl </h3>
We know that, Molarity = Moles ÷ Volume
Rearranging the formula;
Volume = Moles ÷ Molarity
Therefore;
Volume of HCl = 0.165 moles ÷ 0.200M
= 0.825 L
But, 1 L = 1000 mL
= 825 mL
Therefore, the volume of HCl that reacted with CaCO₃ 825 mL
Answer : 5100 KJ
Explanation : In the given reaction of
we can see that 2 moles of Al is producing -850 KJ of energy
so for 12 moles of Al we can calculate as;
12 moles of Al X
= -
5100 KJ
So, we can say that 12 moles of Al will need -5100 KJ of energy.
Explanation 2Al2O3(s)-->4Al(s)+302(g)What is the total number of moles of O2 that are produced when 8.0 mol of Al2O3(s)are totally decomposed ?