Answer:
0.0002 M
Explanation:
<em>The molarity of the HCl required would be 0.0002 M.</em>
First, let us consider the balanced equation of the reaction:
<em>Stoichiometrically, 1 mole of </em>
<em> reacts with 2 moles of </em>
<em> for a complete neutralization reaction.</em>
Recall that: mole = 
Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole
<em>If 1 mole </em><em> requires 2 moles HCl, then 0.0041 mole will require</em>:
0.0041 x 2 = 0.0082 mole HCl
Volume of the HCl = 40.95 L
Molarity = mole/volume
Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M
Answer:
0.15M
Explanation:
NaOH + HCl -->NaCl + H2O
moles of NaOH reacted with HCl
(0.5 × 30)/1000 = 1.5 × 10^ -3
so the moles of HCl reacted with NaOH
1.5 × 10^ -3
concentration of HCl = ( 1.5 × 10^ -3)/10 ×1000
Answer:
- 1 is the correct option
Explanation:
In determining the oxidation state or formal charge on element in an ionic specie, the whole ion need to be equated to the value of charge on the ion.
For example in this case, the charge on the ion is -3. Thus; representing iodine with X and putting -2 for the oxidation state of O (oxygen)
X + -2 = -3 (adding 2 to both side)
X = -3 + 2
X = - 1
Answer : The correct option is, increase amplitude.
Explanation :
Amplitude : It is a measure of the size of sound waves.
The loudness of sound is depend on the amplitude of the sound wave. That means the more the amplitude, the louder will be the sound and the less the amplitude, the low will be the sound.
The loudness of sound does not depend on the tension and wavelength.
Therefore, the correct answer is, increase amplitude.
