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Naya [18.7K]
2 years ago
15

A scientist fills a large, tightly sealed balloon with 75,000 mL of helium at STP.

Chemistry
1 answer:
pav-90 [236]2 years ago
3 0

Considering the definition of STP conditions, 3.35 moles of helium are contained within the balloon.

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Amount of moles of helium within the balloon</h3>

In this case, you know that scientist fills a large, tightly sealed balloon with 75,000 mL of helium at STP.

So, you can apply the following rule of three: if by definition of STP conditions 22.4 liters are occupied by 1 mole of helium, 75 L (75 L= 75000 mL, being 1 L= 1000 L) are occupied by how many moles of helium?

amount of moles of helium=\frac{75 Lx1 mole}{22.4 L}

<u><em>amount of moles of helium= 3.35 moles</em></u>

Finally, 3.35 moles of helium are contained within the balloon.

Learn more about STP conditions:

brainly.com/question/26364483

brainly.com/question/8846039

brainly.com/question/1186356

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A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.

Explanation:

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So, in a Single replacement reaction an uncombined element replaces an element.

<u><em>A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.</em></u>

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A certain radioactive element has a half-life of one hour. If you start with 40.0 grams of the element at noon, how much of the
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A gravel can be broken down into different kinds of substances by physical processes. No chemical reactions are needed to separa
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Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
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\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

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According to stoichiometry :

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