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3 years ago

What is the average translational KE of 5 moles of gas molecules at 300 K?

Physics

1 answer:

aev [14]3 years ago

7 0

Answer:

What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Explanation:

The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

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A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe

marin [14]

Answer:

a) $T_f=305.7049\ K$

b) $\Delta S=313.51\ J.K^{-1}$

Explanation:

Given:

mass of copper, $m_c=2.64\ kg$

initial temperature of copper, $T_{ic}=400\ K$

specific heat capacity of copper, $c_c=385\ J.kg^{-1}.K^{-1}$

mass of water, $m_w=4\ kg$

initial temperature of water, $T_{iw}=300\ K$

specific heat capacity of water, $c_w=4200\ J.kg^{-1}.K^{-1}$

∵No heat is lost in the environment and the heat is transferred only between the two bodies:

Heat rejected by the copper = heat absorbed by the water

$2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)$

$T_f=305.7049\ K$

Now the amount of heat transfer:

$Q=m_c.c_c.(T_{ic}-T_{f})$

$Q=2.64\times 385\times (400-305.7049)$

$Q=95841.5841\ J$

∴Entropy change

$\Delta S=\frac{dQ}{T}$

$\Delta S=\frac{95841.5841}{305.7049}$

$\Delta S=313.51\ J.K^{-1}$

5 0

4 years ago

When all parts of a circuit are composed of conducting materials, the circuit is said to be

den301095 [7]

When all parts of a circuit ... all the way from one terminal of the
battery or power supply to the other terminal ... are composed of
conducting materials, then current can flow in the circuit, and the
circuit is said to be 'closed'.

4 0

4 years ago

A 12.0-m wire with a mass of 145 g is under tension. A transverse wave, for which the frequency is 630 Hz, the wavelength is 0.5

miskamm [114]

Answer:

The maximum traverse acceleration is $\alpha = 31346.095 m/s^2$