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kodGreya [7K]
3 years ago
10

Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction: 2 CO(g) + O2(g) → 2 CO2(g) ∆H for this reac

tion is −135.28 kcal. How much heat would be released if 12.0 moles of carbon monoxide reacted with sufficient oxygen to produce carbon dioxide?
Chemistry
2 answers:
Tom [10]3 years ago
5 0

Answer:

\large \boxed{\text{811.68 kcal}}

Explanation:

It is often convenient to treat the heat of reaction as if it were a reactant or a product. For this reaction, we could write

2CO + O₂ ⟶ 2CO₂ + 135.28 kcal

We could consider the “kcal” as an element with 135.28 as the coefficient in the equation.

The molar ratio would be 135.28 kcal:2 mol CO . Then,

\text{Heat released} = \text{12.0 mol CO} \times \dfrac{\text{135.28 kcal}}{\text{2 mol CO}} = \textbf{811.68 kcal}\\\\\text{The reaction releases $\large \boxed{\textbf{811.68 kcal}}$}

klio [65]3 years ago
4 0

Answer:

Heat released =811.68kcal

Explanation:

2 CO(g) + O2(g) → 2 CO2(g)                 ΔH=-135.28kcal

for this type of question 1st balance the chemical reaction and use unitry method.

From the above balanced equaion it is clearly that,

2 mole of CO reacts with 1 mole of O2 and we have sufficient amount of oxygen means excess amount.

and also for complete consumption of 2 mole of CO, ΔH=-135.28 kcal

for complete consumption of 12 moles of CO2 ΔH=6\times (-135.28kcal)

Heat released =811.68kcal

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Ethylene glycol is used as an antifreeze in car. if 400 g of ethylene glycol is added to 4.00 kg of water, what is the molaity?
Illusion [34]
Data:

solute: ethylene glicol => not ionization

molar mass of ethylene glicol (from internet)  = 62.07 g/mol

solute  = 400 g

solvent = water = 4.00 kg

m =?

ΔTf = ?

Kf = 1.86 °C/mol

Formulas:

m: number of moles of solute / kg of solvent

ΔTf = Kf*m

number of moles of solute = mass in grams / molar mass

Solution

number of moles of solute = 400 g / 62.07 g/mol = 6.44 moles

m = 6.44 mol / 4 kg = 1.61 m <-------- molality (answer)

ΔTf = 1.86 °C / m * 1.61 m = 2.99 °C <---- lowering if freezing point (answer)
8 0
3 years ago
78.0 g of H2O will react with Fe to produce _______ formula units of FeO2 <br> Please help
KengaRu [80]

Answer:

1.306 × 10^24 formula units.

Explanation:

The chemical equation of this qkrstios as follows:

Fe + 2H2O → FeO2 + 2H2

Based on the reaction, 2 mole of H2O produces 1 mole of FeO2

Using the formula as follows;

Mole = mass/molar mass

Molar mass of H2O = 1(2) + 16 = 18g/mol

mole = 78/18

mole = 4.33moles

If 2 mole of H2O reacts to produce 1 mole of FeO2

4.33 moles of H2O will produce 4.33/2 = 2.17moles of FeO2.

To convert moles to formula units, we multiply number of moles by Avagadro number (6.02 × 10^23 units)

= 2.17 moles × 6.02 × 10^23 units

= 13.06 × 10^23

= 1.306 × 10^24 formula units.

3 0
3 years ago
Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
m_a_m_a [10]

Answer:

Explanation:

Let's define positive to be right. The net force on q2 is the

vector sum of the forces from q1 and q3.

The force has a magnitude of and points to the left.

Handling the signs correctly is critical. The negative signs

come from the direction of each of the forces (both to the left),

not from the signs of the charge.

2. Both charges 1 and 3 have 1 close

neighbor and 1 far neighbor. Will

they experience forces of the same

magnitude?

No, because both forces acting on charge 1 are in the same

direction, while the two forces acting on charge 3 are in

opposite directions. Thus, 1 > 3.

Both charges 1 and 2 have two forces acting in the same

direction. Will they experience forces of the same magnitude?

No, because one force acting on charge 1 is the same

magnitude as one acing on charge 2, while the second force

acting on charge 1 is smaller – it comes from a charge farther away

3 0
4 years ago
Which functional group is found in an ester?
Ilya [14]
In my opinion, the answer is the second option.

5 0
2 years ago
A sample of gas has a volume of 20.0 liters at 22.0° C. If the pressure remains constant, what is the volume at 100.0° C?
miv72 [106K]
The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is \frac{ V_{1} }{ T_{1} }=\frac{ V_{2} }{ T_{2} }. We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.
6 0
3 years ago
Read 2 more answers
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