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A block of metal has a mass of 0.0694 kg. It displaces 3.6 mL of water. What is it’s density in g/cm^3

Ivan

Answer:

19.28 g/cm^3 to the nearest hundredth.

Explanation:

The volume of water displaced = the volume of the metal.

density = mass / volume

0.0694 kg = 0.0694 * 1000

= 69.4 g.

Density = 69.4 / 3.6

= 19.28 g/cm^3.

4 0

4 years ago

Which of these lab safety procedures is INCORRECT?

Ksju [112]

Answer:

D

Explanation:

D is not necessary to follow lab safety in Laboratory

6 0

3 years ago

Write the net ionic equation:. . A solution of diamminesilver(I) chloride is treated with dilute nitric acid

zimovet [89]

Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl 
or
Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl this the complete balanced equation
now remove spectator ions to get net ionic equation
so

 2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3- 2NO3- 2H+ [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
hope it helps

5 0

3 years ago

Read 2 more answers

Indicate the changes (increases, decreases, does not change) in its volume when the pressure undergoes the following changes at

Inga [223]

The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, Pressure, Volume and Temperature of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the Boyle's Law can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

Final P (P₂) = 6

P₁.V₁ = P₂.V₂

2.V = 6.V₂

V₂ = 1/3V

When the pressure increases to 6 atm, volume decreases by 1/3.

For case 2.)

P₁ = 2

V₁ = V

P₂ = 0.4

2.V = 0.4V₂

V₂ = 5V

When pressure drops to 0.4 atm, volume increases by 5.

For case 3.)

Since there are no change in the pressure, the volume is the same from the beginning, so does not change.

8 0

3 years ago

How will you recognize that a single replacement reaction has occured when you combine an active metal with 6m hcl?

frez [133]

A single replacement or displacement reaction occurs when one ingredient in a compound replaces another. Only another metal can replace a less active one; a metal can only displace another metal, and a non-metal can only displace another non-metal.

<h3>Displacement reaction:</h3>

The tendency of the element to lose electrons is what makes it metallic. Due to their bigger sizes and propensity to lose electrons as size, the number of shells, and nuclear force of attraction rise, the most active metals are found on the left side of the periodic table.

The reaction in which the more reactive element displaces the less reactive element is known as the displacement reaction.

When we combine an active metal with HCl, the reaction is as follows:

We are taking sodium, Na which is the most active metal. It will replace H in HCl because it is more reactive than H.

2Na + 2HCl → 2NaCl + H₂

Three ways to recognize if a single displacement reaction has taken place:

1. Color change

2. Formation of bubbles (a gas)

3. Formation of a precipitate

Learn more about displacement reaction here:

brainly.com/question/15343606

#SPJ4

8 0

2 years ago