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Rashid [163]
3 years ago
13

The specific heat of aluminum is 0.897 J/g•°C. Which equation would you use to calculate the amount of heat needed to raise the

temperature of 0.75 g of aluminum from 7°C to 29°C? A. Q = 0.75 g x 0.897 J/g•°C x 22°C B. Q = 0.75 g x 0.385 J/g•°C x 29°C C. Q = 0.75 g x 0.385 J/g•°C x 22°C D. Q = 0.75 g x 0.897 J/g•°C x 29°C
Chemistry
1 answer:
docker41 [41]3 years ago
6 0
Q = 0.75 g x 0.897 J/g•°C x 22°C
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In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

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3 years ago
What happens to the ionizing rate if the steps of ionizing polyprotic acid increases?
Tanzania [10]

Answer:

<h3>An acid that contains more than one ionizable proton is a polyprotic acid. The protons of these acids ionize in steps. The differences in the acid ionization constants for the successive ionizations of the protons in a polyprotic acid usually vary by roughly five orders of magnitude.</h3>
5 0
2 years ago
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Question 4 (1 point)
Diano4ka-milaya [45]

In an endothermic reaction products are <u>HIGHER </u>than reactants in potential energy and <u>LESS </u>stable.

Explanation:

Energy is input into the reaction in an endothermic reaction. This means the products are of a higher energy level than the reactants. Therefore the reaction increases Gibb's free energy and reduces entropy. Remember in thermodynamic stability involves an increase in entropy and a decrease in Gibbs free energy. Therefore the products are less stable than the reactants. This is why endothermic reactions do not occur spontaneously like exothermic reactions.

6 0
3 years ago
How many moles of HCl are in 30.00mL of a 0.1000M HCl solution? A. 0.003000mol. B. 300.0mol C. 0.03000mol D. 3.000mol
Katyanochek1 [597]

Given the volume of HCl solution = 30.00 mL

Molarity of HCl solution = 0.1000 M

Molarity, moles and volume are related by the equation:

Molarity = \frac{Moles of solute}{Volume of solution (L)}

Converting volume of HCl from mL to L:

30.00 mL * \frac{1 L}{1000mL}=0.030000 L

Calculating moles of HCl from volume in L and molarity:

0.03000 L * \frac{0.1000mol}{L}= 0.003000 mol HCl

The final moles would be reported to 4 sig figs. So the correct answer will be 0.03000 mol HCl

Correct option: C. 0.03000mol

7 0
3 years ago
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