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2 years ago

6

If the following arithmetic operations are carried out, how many significant figures should be reported in the answer?32 + 0.56

+ 0.210 + 3.3

1 answer:

PtichkaEL [24]2 years ago

6 0

Answer:

2

Explanation:

The least number of significant figures in any term is 2.

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What is the oxidation state of each individual carbon atom in c2o42−?

MA_775_DIABLO [31]

Answer:

+3

Explanation:

The oxygen all have a -2 oxidation state. (peroxides are exceptions)

The chemical structure is symmetrical. Both carbon are equivalent.

2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.

2 (oxidation state of carbon) + 4 (-2) = -2

oxidation state of carbon = +3

7 0

3 years ago

Read 2 more answers

A 25.0 ml sample of water at 90 °c has a mass of 24.12 g. Calculate the density of water at this temperature.

ycow [4]

solution:

Density of water the density of water is greatest at about four degrees C (39.2Â° F or 277degrees Kelvin) which is a density of 1.000 kg per liter (62.4 pounds per cubic foot). Liquids expand slightly as their temperature is raised, but liquid water is denser than solid water (ice). That is why ice floats: it is less dense than liquid water. That is due to the crystal structure of ice. When water freezes, its volume increases about nine percent. 277 K. Density rho = mass m / Volume V. Water has a density of 1,000 kg/m3 = 1,000 g/L = 1.000 kg/dm3 = 1.000 kg/L = 1.000 g/cm3 = 1.000 g/mL at the temperature of 3.98 degrees Celsius. Temperature in degrees Celsius and the density of water: 1

At 4 Â°C, its density is the greatest and is equal to 1000 kilograms per cubic meter (SI unit). At any other temperature, its density is less than 1000 kilograms per cubic meter. The answer "1.0" is wrong. Water is unique in that it is one of the only substances that actually expands and becomes less dense as the temperature increases. Water molecules (H 2 O) have a special shape and arrangement; this is why ice floats above the warmer water on a frozen lake. To convert grams/cm3 or grams/mL (1 cm 3 = 1 mL) into other units, use these conversions: 1 dry ounce = 28.349 grams 1 fluid ounce = 29.574 mL so to go from grams/cm 3 to dry ounces per fluid ounce, multiply by 0.9586.

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4 years ago

Add the following thermochemical equations: (1) P4(s) + 6Cl2(g) => 4PCl3(g) ΔH = –1148 kJ (2) 4PCl3(g) + 4Cl2(g) => 4PCl5(

eimsori [14]

Answer:

the overall reaction is

P4(s) + 10Cl2(g) => 4PCl5(g)

and its ΔH is

ΔH overall = (-1608 KJ)

Explanation:

given that

P4(s) + 6Cl2(g) => 4PCl3(g) , ΔH1 = –1148 kJ

4PCl3(g) + 4Cl2(g) => 4PCl5(g) , ΔH2 =–460 kJ

summing both equation gives

P4(s) + 6Cl2(g) +4PCl3(g) + 4Cl2(g) => 4PCl3(g) + 4PCl5(g)

but 4PCl3(g) is in both sides , so is cancelled out

P4(s) + 6Cl2(g)+ 4Cl2(g) => 4PCl5(g)

summing the Cl2(g)

P4(s) + 10Cl2(g) => 4PCl5(g) → overall reaction

(can be verified that the reaction is balanced)

since we sum both equations the ΔH of the overall reaction is also the sum of the ΔH of the individual reactions.

ΔH overall = ΔH1 + ΔH2 = (–1148 kJ) + (–460 kJ) = (-1608 KJ)

4 0

3 years ago

An intravenous infusion is to contain 15 mEq of potassium ion and 20 mEq of sodium ion in 500 mL of 5% dextrose injection. Using

Studentka2010 [4]

Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

Explanation:

1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl

in intravenous infusion 15 mEq of K are:

15x75mg KCl = 1,125g of KCl

And 20 mEq of Na are:

20x59mg NaCl = 1,18g of NaCl

To supply the potassium ion it is necessary to inject:

1,125g of KCl× $\frac{30mL}{6g}$ =<em> 5,6mL of 6g/30mL solution</em>

And, to supply the sodium ion it is necessary to inject:

1,18g of NaCl× $\frac{100mL}{0,9g}$ = <em>131,1 mL of 0,9% solution</em>

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I hope it helps!

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4 years ago

Which of the following would double the pressure on a contained gas at constant temperature? A. doubling the volume of the conta

lesantik [10]

A. Doubling the volume of the container

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4 years ago