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Mass is density times volume
0.760 x 531 = 403.56g
404g if 3 sig figs
Answer:0.286M
Explanation:
10.7g / 149.89g/mol×0.25L
The empirical and molecular formulas will be
and
respectively.
<h3>Empirical and molecular formula</h3>
The compound contains C, H, and O.
C = 61.15/12 = 5.0958
H = 5.3/1 = 5.3
O = 31.55/16 = 1.9719
Divide by the smallest
C = 2.6
H = 2.7
O = 1
Thus, the empirical formula is 
Empirical formula mass = (12x5) + (1x5) + 16x2 = 97
n = 152.15/97 = 2
The molecular formula is 
More on molecular and empirical formulas can be found here: brainly.com/question/14425592
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Use the molar mass of ammonia to change the grams to moles and then use mole-mole ratio
100. g NH3 (1 mol NH3/ 17.04 g) (3 mol H2/ 2 mol NH)= 8.80 moles H2