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3 years ago

Which group of elements would generally have the

Chemistry

2 answers:

True [87]3 years ago

5 0

Group 1a because atom size decreases going left to right

nikklg [1K]3 years ago

4 0

Group 1A

As the atomic number of elements in Period 3 (Atomic number 11-18) increases, the atomic radius decreases. The atom with the largest atomic radius is Na which is located in the group 1.
This is because, the effect of increasing proton number is greater than that of the increasing effective nuclear charge; therefore, there is a greater nuclear attraction. The valence electrons are held closer towards the nucleus of the atom. As a result, the atomic radius decreases.

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You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio

irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

Substituting the respective values ,

M₁ * 125.0 mL = 4.56 M * 134.1 mL

M₁ = 4.90 M

6 0

3 years ago

Hi! I really really need help roght now please help me and if u put whatever in the chas as in just to get points i will ban you

dolphi86 [110]

The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:

The population of mice is in an environment with many black rocks
Mice with black for are more likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have black fur
A sandstorm covers most of the population's environment with brown sand
Mice with black fur are less likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have brown fur

<h3>What is the correct order for natural selection in the desert environment given?</h3>

Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:

The population of mice is in an environment with many black rocks
Mice with black for are more likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have black fur
A sandstorm covers most of the population's environment with brown sand
Mice with black fur are less likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have brown fur

Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.

Learn more about about adaptation at: brainly.com/question/25594630

8 0

2 years ago

The lab procedure mentions that not all of the oxone may dissolve after being added to the water because the water may be satura

ollegr [7]

Answer:

The answer is (C) There are more solute molecules than water molecules.

Explanation:

A saturated solution is one in which no more solute can be dissolved or disintegrated into the solvent. When or if the ozone stops being dissolved in the water, it implies that the water has already taken on more ozone molecules than it can contain, meaning there are more solute molecules (ozone molecules) than there are solvent molecules (water molecules).

3 0

2 years ago

Read 2 more answers

What characterizes a strong acid or base? complete ionization in water polar covalent bonding presence of a hydroxide or hydroge

Natasha2012 [34]

1. Complete ionization in water.

2. Ionization constant.

3. A good hydrogen-ion acceptor.

4. Weak acid.

5. This base ionizes slightly in aqueous.

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7 0

3 years ago

Read 2 more answers

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

$CuBr\rightleftharpoons Cu^++Br^-$