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stich3 [128]
4 years ago
14

Consider the half reaction below.

Chemistry
1 answer:
allsm [11]4 years ago
6 0

Answer:

balancing of charges of both sides

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What force on Earth can affect the pull of gravity?
MakcuM [25]

Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass.

7 0
3 years ago
Read 2 more answers
Methanethiol, CH3SH, has a substantial dipole mement (1.52) even though carbon and sulfer have identical electronegativities. Ex
AleksAgata [21]

Answer:

The whole molecule is polar because Sulfur has lone pairs but Carbon doesn't. Lone pairs count more toward polarity, shifting dipole toward S.

Explanation:

Even though carbon and sulfur have identical values of electronegativities, the molecule, CH_3SH is polar because of the presence of the lone pairs on the sulfur atom.

The C-S bond is not polar because the both the atoms have electronegatiivty. <u>But S has lone pairs which can attract the bond pairs of the bond between the S and H and thus acquires slightly negative charge and H acquires slightly positive charge.</u>

6 0
3 years ago
30 POINTS
Pavlova-9 [17]
Because neither can be created or destroyed
7 0
3 years ago
3 ml of a 400 mg/L solution of a dye is diluted with enough water to give a total volume of 10 mL \. Calculate the concentration
In-s [12.5K]

Answer:

120

Explanation:

SIMPLE PROPORTION

8 0
3 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
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