If the detector is capturing 3.3×108 photons per second at this wavelength, what is the total energy of the photons detected in
1 answer:
Answer:
The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J
Explanation:
The energy carried by electromagnetic radiation is displaced by waves. This energy is not continuous, but is transmitted grouped into small "quanta" of energy called photons. The energy (E) carried by electromagnetic radiation can be measured in Joules (J). Frequency (ν or f) is the number of times a wave oscillates in one second and is measured in cycles / second or hertz (Hz). The frequency is directly proportional to the energy carried by a radiation, according to the equation: E = h.f, (where h is the Planck constant = 6.63 · 10⁻³⁴ J / s).
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. it is expressed in units of length (m). In light and other electromagnetic waves that propagate at the speed of light (c), the frequency would be equal to the speed of light (≈ 3 × 10⁸ m / s) between the wavelength :
So:
In this case, the wavelength is 3.35mm=3.35*10⁻³m and the energy per photon is:
E=5.93*10⁻²³
The detector is capturing 3.3*10⁸ photons per second. So, in 1 hour:
E=7.04*10⁻¹¹
The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J
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Answer : The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation :
Standard formation of reaction : It is a chemical reaction that forms one mole of a substance from its constituent elements in their standard states.
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, we get :
(1)
(2)
(3)
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of methanol is, -238.7 kJ/mole