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2 years ago

Plz help I’ll mark brainliest

Chemistry

2 answers:

Sauron [17]2 years ago

6 0

Answer:

an increase in the consumption of fossil fuels

Explanation:

industrialization is the bulid of bulidings and factories it would not kill off humans or cool global climate if anything its destroying the outter layers protecting us from the sun with the smoke and air poultion it causes so it would be hotter and definitely wouldn't decrease air and water population

Neko [114]2 years ago

4 0

Answer:

Industrialization has historically led to urbanization by creating economic growth and job opportunities that draw people to cities. Urbanization typically begins when a factory or multiple factories are established within a region, thus creating a high demand for factory labor.

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In which environment would a forensic scientist not be found?

mrs_skeptik [129]

The correct answer is D. In a police interrogation room, questioning the suspect.

Explanation:

Forensic scientists are experts who use science as part of criminal investigations. Indeed, the main role of these experts is to deal with the evidence related to the crime to help authorities understand how the crime occurred and who was involved in this.

Because of this, the forensic scientist's role includes collecting evidence, analyzing samples, participating as witnesses in trials, and in some cases teach other experts about techniques. However, forensic scientists cannot interrogate suspects as they only deal with evidence and this process is in charge of the police.

6 0

3 years ago

Chromatin consists of long strands of material located within the nuclear membrane.

Dmitry_Shevchenko [17]

Answer:

True

Explanation:

4 0

3 years ago

If the solvent front is 68 mm and the ring front of an unknown is 48mm from the original spot, what is the rf value?

Nat2105 [25]

Given:

Distance of solvent front = 68 mm

Distance of unknown = 48 mm

To determine:

The rf value

Explanation:

The retention factor or the rf value is given by the ratio of distance traveled by the unknown to the distance traveled by the solvent front

RF = distance by unknown/distance by solvent

RF = 48/68 = 0.706

Ans: the RF value is 0.706

3 0

3 years ago

The method used in this experiment is sometimes called the vapor density method. The ideal gas equation can be rearranged to sol

TiliK225 [7]

The correct answer for the question that is being presented above is this one: "B) Temperature."
Here are the following choices:

A) all of these measurements are needed

B) Temperature

C) Molar Mass

D) Pressure

E) Mass

6 0

2 years ago

Consider the equilibrium between SbCl5, SbCl3 and Cl2. SbCl5(g) -->SbCl3(g) + Cl2(g) K = 2.30×10-2 at 566 K .The reaction is

Arte-miy333 [17]

Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

The equilibrium constant of the reaction in 7.40 L = $K_c$

$K_c=2.30\times 10^{-2}$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in volume

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place. As the number of moles of gas molecules is greater at the product side. So, the equilibrium will shift in the right direction.

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

Concentration of $SbCl_5$ in 7.40 L = 0.333 M

Moles of $SbCl_5$ in 7.40 L:

$=0.333 M\times 7.40 L=2.4642 mol$

Concentration of $SbCl_3$ in 7.40 L = $8.75\times 10^{-2} M$

Moles of $SbCl_3$ in 7.40 L:

$=8.75\times 10^{-2} M\times 7.40 L=0.6453 mol$

Concentration of $Cl_2$ in 7.40 L = $8.75\times 10^{-2} M$

Moles of $Cl_2$ in 7.40 L:

$=8.75\times 10^{-2} M\times 7.40 L=0.6453 mol$

On adding all these compounds in new container of volume of 14.8 L, equilibrium will reestablish and there initial concentration of all the compounds will change;

Concentration of $SbCl_5$ in 14.8 L = $\frac{2.4642 mol}{14.8 L}=0.1665 M$