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ArbitrLikvidat [17]
3 years ago
11

Between this and the next assignment, we want to get a better under- standing of how light interacts with the eye. Here are two

questions to get us started, focused on diffraction (i.e., the spreading of light when it passes through a narrow opening). A. To regulate the intensity of light reaching our retinas, our pupils1 change diameter anywhere from 2 mm in bright light to 8 mm in dim light. Find the angular resolution of the eye for 550 nm wavelength light at those extremes. In which light can you see more sharply, dim or bright
Physics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

θ₁ = 3.35 10⁻⁴ rad ,  θ₂ = 8.39 10⁻⁵ rad

Explanation:

This is a diffraction problem for a slit that is described by the expression

       sin θ = m λ

the resolution is obtained from the angle between the central maximum and the first minimum corresponding to m = 1

      sin θ = λ / a

as in these experiments the angle is very small we can approximate the sine to its angle

        θ = λ / a

In this case, the circular openings are explicit, so the system must be solved in polar coordinates, which introduces a numerical constant.

       θ = 1.22 λ / D

where D is the diameter of the opening

 let's apply this expression to our case

indicates that the wavelength is λ = 550 nm = 550 10⁻⁹ m

the case of a lot of light D = 2 mm = 2 10⁻³ m

       θ₁ = 1.22 550 10-9 / 2 10⁻³

       θ₁ = 3.35 10⁻⁴ rad

For the low light case D = 8 mm = 8 10⁻³

      θ₂ = 1.22 550 10-9 / 8 10⁻³

      θ₂ = 8.39 10⁻⁵ rad

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Select the statement that correctly completes the description of phase difference.
KengaRu [80]

Answer:

The difference in the phase angle between any two waves at any given position along the waves.

Explanation:

Phase difference describes  the difference in the phase angle between any two waves at any given position along the waves. The equation of wave is given by :

Wave 1, y=A\ sin(\omega t)

Wave 2, y=A\ sin(\omega t+\phi)

Where

A is the amplitude of wave

\omega is the angular frequency

\phi is the phase difference between two waves

If \Delta d is the path difference, it is given by :

\Delta d=d\ sin\theta

Hence, the correct option is (a) "the difference in the phase angle between any two waves at any given position along the waves".

3 0
4 years ago
When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rat
svlad2 [7]

Answer:

343/1500

Explanation:

Power: This can be defined as the product force and velocity. The S.I unit of power is Watt (w).

From the question,

P' = mg×v................. Equation 1

Where P' = power used to gain an altitude, m = mass of the engine, g = acceleration due to gravity of the engine, v = velocity of the engine.

Given: m = 700 kg, v = 2.5 m/s, g = 9.8 m/s²

Substitute into equation 1

P' = 700(2.5)(9.8)

P' = 17150 W.

If the full power generated by the engine = 75000 W

The fraction of the engine power used to make the climb = 17150/75000

= 343/1500

8 0
3 years ago
In dim light
faltersainse [42]

The Answer is A, the iris dilates the pupil.

4 0
3 years ago
Read 2 more answers
What is the acceleration due to gravity at an altitude of 116?
Schach [20]
Gravitational acceleration (Ga) is  inversely proportional to  k / Distance^2

so Ga * Distance^2 = K

On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).

So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km

As 
Ga = k / distance^2 

Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169

= 9.45 m/s^2 to 2sf
7 0
4 years ago
A 40.0-μFcapacitor is connected across a 60.0 Hz generator. An inductor is then connected in parallel with the capacitor. What i
amm1812

Answer:

The value of the inductance is 175.9 mH.

Explanation:

Given that,

Capacitor C= 40.0\ \muF

Frequency = 60.0 Hz

The inductor and capacitor is connected in parallel, the voltage across each of these elements is the same.

We have,

V_{L}=V_{C}

Using ohm's law

I_{rms}\times X_{L}=I_{rms}\times X_{C}

X_{L}=X_{C}

2\pi f L=\dfrac{1}{2\pi f C}

L=\dfrac{1}{4\pi^2\times f^2\times C}

Put the value into the formula

L=\dfrac{1}{4\times\pi^2\times60.0^2\times40\times10^{-6}}

L=0.1759\ H

L=175.9\times10^{-3}\ H

L=175.9\ mH

Hence, The value of the inductance is 175.9 mH.

5 0
4 years ago
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