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FromTheMoon [43]
3 years ago
8

Una pelota de golf se lanza con una rapidez de 50 m/seg y un ángulo de elevación de 40º. Calcular:

Physics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

good morning you are you still

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A drone is flying horizontally when it runs out of battery and begins to free fall from 20m. No drag. If it lands 60m away (in t
rewona [7]

Answer:

Explanation:

Remark

At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.

Givens

h = 20 m

hd = 60 m

g = 9.81

vi = 0

Formula

d = vi*t + 1/2 a * t^2                  We are solving for t

Solution

When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters

d = 0*t + 1/2 * 9.81 a* t^2

20 = 4.91 * t^2                          Divide by 4.91

20/4.91 = 4.91 t^2 / 4.91    

4.073 = t^2                              Take the square root of both sides.

t = 2.02 seconds

Horizontal

d = 60 m

t = 2.02 seconds

v = ?

Note: there is no horizontal deceleration or acceleration

v = d/t

v = 60/2.02

Answer: v = 29.73 m/s

3 0
2 years ago
Need an answer asap please!
olya-2409 [2.1K]

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Explanation:

7 0
3 years ago
Classify the quadrilateral. parallel sides are indicated with arrows.
Sonbull [250]
A quadrilateral is a four-sided polygon that may be classified as: trapezoid, rectangle, square, rhombus, etc. This classification is based on the measurement of the four angles, the four sides, and their being parallel. Unfortunately though, I think you missed to include here the diagram that we are about to classify. 
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3 years ago
Adaptive organ of duck​
postnew [5]

Answer:

brain

Explanation:

                       

6 0
3 years ago
What is the current in mA through a 500 Ω resistor that is connected to a 1.5 V battery? Show all calculations using Ohm’s law (
Ludmilka [50]

Answer:

3 mA.

Explanation:

The following data were obtained from the question:

Resistor (R) = 500 Ω

Potential difference (V) = 1.5 V

Current (I) =.?

Using the ohm's law equation, we can obtain the current as follow:

V = IR

1.5 = I x 500

Divide both side by 500

I = 1.5 / 500

I = 3×10¯³ A.

Therefore, the current in the circuit is 3×10¯³ A.

Finally, we shall convert 3×10¯³ A to milliampere (mA).

This can be obtained as follow:

Recall:

1 A = 1000 mA

Therefore,

3×10¯³ A = 3×10¯³ × 1000 = 3 mA

Therefore, 3×10¯³ A is equivalent to 3 mA.

Thus, the current in mA flowing through the circuit is 3 mA.

3 0
3 years ago
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