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3 years ago

Una pelota de golf se lanza con una rapidez de 50 m/seg y un ángulo de elevación de 40º. Calcular:

Physics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

good morning you are you still

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A hot air balloon contains 85,000 moles of air. To what temperature must the

Oksi-84 [34.3K]

Answer:

B is the best answer for this question

8 0

3 years ago

A father racing his son has 1/3 the kinetic energy of the son, who has 1/4 the mass of the father. The father speeds up by 1.5 m

Feliz [49]

Explanation:

Let the speeds of father and son are $v_f\ and\ v_s$ . The kinetic energies of father and son are $K_f\ and\ K_s$ . The mass of father and son are $m_f\ and\ m_s$

(a) According to given conditions, $K_f=\dfrac{1}{3}K_s$

And $m_s=\dfrac{1}{4}m_f$

Kinetic energy of father is given by :

$K_f=\dfrac{1}{2}m_fv_f^2$ .............(1)

Kinetic energy of son is given by :

$K_s=\dfrac{1}{2}m_sv_s^2$ ...........(2)

From equation (1), (2) we get :

$\dfrac{v_f^2}{v_s^2}=\dfrac{1}{12}$ ..............(3)

If the speed of father is speed up by 1.5 m/s, so the ratio of kinetic energies is given by :

$\dfrac{K_f}{K_s}=\dfrac{1/2m_f(v_f+1.5)^2}{1/2m_sv_s^2}$

$v_s^2=4(v_f+1.5)^2$

Using equation (3) in above equation, we get :

$v_f=\dfrac{1.5}{\sqrt3-1}=2.04\ m/s$

(b) Put the value of $v_f$ in equation (3) as :

$v_s=7.09\ m/s$

Hence, this is the required solution.

8 0

3 years ago

How many nanoseconds are there in 1.90 yr ?<br> Express your answer using three significant figures.

shepuryov [24]

   (1.9 yr) x (365.24 day/yr) x (86,400 sec/day) x (10⁹ nsec/sec)

   = (1.9 x 365.24 x 86,400 x 10⁹) nanosec

   = 6.00 x 10¹⁶ nanoseconds

5 0

3 years ago

On a sunny day, a student poured a cup of water on the sidewalk to make a puddle. When he returned later, the puddle was gone. T

ivanzaharov [21]

Answer:

The students conclusion is wrong.

Explanation:

The students conclusion is wrong because liquids can not soak into concrete. The water evaporated because it was a hot sunny day. The water turned into a gas called water vapor.

8 0

3 years ago

An average human weighs about 600 N

NemiM [27]

Answer:

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

<em> $F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}$ </em>

Where,

$\frac{1}{4\pi\epsilon_{0}}$ = 9 x 10⁹ N m² C⁻²

Therefore

x² = 9 x 10⁹ X 1.5² / 600

= 33750000

x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

4 0

3 years ago