Particle Size
Temperature
Concentration
Difference
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Diffusion distance
Yes it will thats the same question I got
Answer:
94.28 cm
Explanation:
The formula for elastic potential energy is given as;
PEel = 1/2 *k*x² where x is the displacement, k is the spring constant
Given
PEel = 110 J, k= 350 N/m then find x
PEel = 1/2 *k*x²
110 = 1/2 * 350 * x²
110 = 175 x²
110/175 = x²
0.6286=x²
√0.6286 =x
0.7928 m = x
79.28 cm = x
New length of spring = 15 cm + 79.28 cm = 94.28 cm
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u><em> </em><em>F</em><em>a</em><em>l</em><em>s</em><em>e</em>
<u>E</u><u>x</u><u>p</u><u>l</u><u>a</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>
<em>False because it can leads to overloading and further to short circut.</em>
<h2>
<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>I</u></em><em><u>t</u></em><em><u> </u></em><em><u>W</u></em><em><u>i</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>H</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>Y</u></em><em><u>o</u></em><em><u>u</u></em><em><u>!</u></em></h2>
The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. A good comparison of the nucleus to the atom is like a pea in the middle of a racetrack. (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.)
