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Vikentia [17]
2 years ago
15

Across:

Physics
1 answer:
vladimir2022 [97]2 years ago
6 0

Answer:

it would be c i just had it

Explanation:

welcome................

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A stubborn 130 kg pig sits down and refuses to move. to drag the pig to the barn, the exasperated farmer ties a rope around the
TEA [102]
<span>Unless the pig moves static friction acts on it once the pig starts moving kinetic friction comes in to play so when the pig is not moving=frictional force acting on it =normal force*co-efficient of static friction.</span>
7 0
4 years ago
What is the magnitude of the net torque on the pulley about the axle?
jeyben [28]

Answer: Torque= tangential force × radius of the pulley

Explanation:

Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.

For a pulley, the torque T= tangential force × radius of the pulley

Pulleys can be used in combination also to achieve a desired output.

6 0
4 years ago
How are electricity and magnets connected?
Stella [2.4K]

Answer:

Magnets are employed to generate electricity.

Explanation:

Magnets' characteristics are employed to generate electricity. Electrons are pulled and pushed by moving magnetic fields. When you move a magnet around a coil of wire, or a coil of wire around a magnet, the electrons in the wire are pushed out and an electrical current is created.

3 0
3 years ago
Read 2 more answers
How is wind direction indicated on a weather map ?
kotegsom [21]
It uses arrows to show what way the wind is going
6 0
3 years ago
Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the
Assoli18 [71]

Answer:

Part a)

\rho = 3\epsilon_0 k r^2

Part b)

Q = 4\pi \epsilon_0kR^5

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

E = kr^3 \hat r

now electric flux through a spherical surface of radius r is given as

\phi = E. A

\phi = kr^3(4\pi r^2)

now by Guass law we know that

E.A = \frac{q}{\epsilon_0}

q = 4\pi \epsilon_0kr^5

now volume charge density is given as

\rho = \frac{q}{\frac{4}{3}\pi r^3}

\rho = 3\epsilon_0 k r^2

Part b)

Total charge inside the radius R is given as

Q = 4\pi \epsilon_0kR^5

7 0
3 years ago
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