Answer:
15944.6 sec
Explanation:
d = distance of Pluto from earth = 32 AU = 32 x 1.496 x 10¹¹ m
v = speed of light = 1.08 x 10⁹ km/hr = ( 1.08 x 10⁹) (0.278) m/s
t = time taken for the communication to reach from probe to earth = ?
Using the equation
d = v t
Inserting the values given
32 x 1.496 x 10¹¹ = (( 1.08 x 10⁹) (0.278)) t
t = 15944.6 sec
t = 1.6 x 10⁴ sec
Answer:
50000 μT
Explanation:
From the given information:
the diameter of the loop = 1.0 mm = 0.001 m
no of turns (N) = 200
current (I) = 0.199 A
radius = d/2 = 0.001/2
= 5 × 10⁻⁴ m
Recall that;
the magnetic field at the centre of circular wire is:


= 0.05 T
= 50000 μT
Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:
the earth's magnetic field = 50000 μT
Answer:
The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2
Explanation:
Given that

From equation of normal strain in x direction:

Substituting the values:

Answer:
b) 68,9 km/h a) picture
Explanation:
In this problem, since velocity is expressed in km/h and time in minutes, we have to convert either time to hours or velocity to km/min. It is easier to use hours.
Using this formula we pass time to hours:

Now we can plot speed vs time (image 1). The problem says that the driver uses constant speed, so all lines have to be horizontal.
Using the values of the speed we calculate the distance in each interval

Using these values and the fact that she was having lunch in the third one (therefore stayed in the same position), we plot position vs time, using initial position zero (image 2, distance is in km, not meters).
Finally, we compute the average speed with the distance over time:
