Question

Help me please!!!!!!!!!!!!

Answer 1

Answer: B. 448.0 moles

Explanation:

The balanced chemical equation is :

$2NBr_3+3NaOH\rightarrow N_2+3NaBr+3HOBr$

According to stoichiometry :

3 moles of $NaOH$ produce = 1 mole of $N_2$

Thus 48.00 moles of $NaOH$ will produce =$\frac{1}{3}\times 48.00=16.00moles$  of $N_2$

Mass of $N_2=moles\times {\text {Molar mass}}=16.00moles\times 28g/mol=448.0g$

Thus 448.0 g of $N_2$ will be produced from 48.00 moles of NaOH.