Answer:
chloroplasts, cell walls, or intracellular vacuoles
Explanation:
You didn't list the following, but I'm guessing it is chloroplasts, cell walls, or intracellular vacuoles
Answer:
8
Explanation:
The atomic number refers to the number which identifies the element, which is the proton number.
Two sublevels of the same principal energy level differ from each other through shape and size.
There are mainly 4 energy level s, p, d and f.
The s level has one orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 2.
The p level has three orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 6.
The d level has five orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 10.
The f level has 7 orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 14.
They may be differ in magnetic level.
Thus, we concluded that Two sublevels of the same principal energy level differ from each other through shape and size.
learn more about energy level:
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I don't know what the problem is, but here are some rues to help you out:
- All non-zero figures are significant
- When a zero falls between non-zero digits, that zero is significant.
- When a zero falls after a decimal point, that zero is significant.
- When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
- When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
1.062 mol/kg.
<em>Step 1</em>. Write the balanced equation for the neutralization.
MM = 204.22 40.00
KHC8H4O4 + NaOH → KNaC8H4O4 + H2O
<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)
Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)
= 4.035 mmol KHP
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)
= 4.035 mmol NaOH
<em>Step 4</em>. Calculate the mass of the NaOH
Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)
= 161 mg NaOH
<em>Step 5</em>. Calculate the mass of the water
Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g
= 37.973 g
<em>Step 6</em>. Calculate the molal concentration of the NaOH
<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg
