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wariber [46]
3 years ago
13

When naming organic compounds, there are strict rules regarding punctuation?

Chemistry
1 answer:
melisa1 [442]3 years ago
3 0

The rules for naming an organic compound regarding punctuation are

a) a comma is put in between two digits (or numbers)

b) a digit and a letter are separated by a hyphan

Example:

3-ethyl-2-methylhexane

2,3,3-trimethylhexane



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If a 10.0ml sample of unknown liquid has a mass of 7.553g what is the density of the unknown liquid
Burka [1]

The density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml

<h3>What is density?</h3>

Density is the measurement of how tightly a material is packed together.

Given data:

Weight =7.553g

Volume = 10.0ml

Density =\frac{mass}{volume}

Density =\frac{7.553g}{10.0ml}

Density = 0.7553 g/ml

Hence, the density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml.

Learn more about density here:

brainly.com/question/15164682

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6 0
2 years ago
Which of the following elements has the greatest atomic radius?<br> Al<br> S<br> Si<br> C
suter [353]

Answer:

The answer to your question is: Al, Si have the greatest and S, C have the smallest.

Explanation:

Atomic radius increases from right to left in the periodic table.

Atomic radius increases from the upper section to the lower section of the periodic table.

Order of the atomic radius from highest to lowest.

Al, Si, S and C

6 0
3 years ago
What is the percent yield of a reaction in which 51.5 g of tungsten(VI) oxide (WO3) reacts with excess hydrogen gas to produce m
Rus_ich [418]

Answer:

The percent yield of a reaction is 48.05%.

Explanation:

WO_3+3H_2\rightarrow W+3H_2O

Volume of water obtained from the reaction , V= 5.76 mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 5.76 mL=5.76 g

Theoretical yield of water : T

Moles of tungsten(VI) oxide = \frac{51.5 g}{232 g/mol}=0.2220 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2220 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2220 mol=0.6660 mol

Mass of 0.6660 moles of water:

0.666 mol × 18 g/mol = 11.988 g

Theoretical yield of water : T = 11.988 g

To calculate the percentage yield of reaction , we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{m}{T}\times 100=\frac{5.76 g}{11.988 g}\times 100=48.05\%

The percent yield of a reaction is 48.05%.

7 0
3 years ago
Read 2 more answers
Which forces can be classified as intramolecular?
just olya [345]

Answer:

D) Covalent Bonds

Explanation:

Quizlet says so

7 0
3 years ago
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Special characteristics of metals, like being shiny, are called A Descriptions B Phrases C Qualities D Properties
slega [8]
Answer:
d properties
i took a test on this before
8 0
3 years ago
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