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2 years ago

When naming organic compounds, there are strict rules regarding punctuation?

Chemistry

1 answer:

melisa1 [442]2 years ago

3 0

The rules for naming an organic compound regarding punctuation are

a) a comma is put in between two digits (or numbers)

b) a digit and a letter are separated by a hyphan

Example:

3-ethyl-2-methylhexane

2,3,3-trimethylhexane

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Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

2 years ago

Which of the following are covalent compounds? Select all that apply. CaO CO2 KBr NO

Sergeeva-Olga [200]

Answer

CO2 and NO are covalent

Explanation:

Which of the following are covalent compounds? Select all that apply.

CaO

CO2

KBr

the atoms ib covalent compounds share electron pairsO

CaO and KBr are ioinic

CO2 and NO are covalent

3 0

2 years ago

How many moles of cesium xenon heptafloride can be produced from the reaction 12 mol cesium Floride with 14 mol xenon hexaflorid

neonofarm [45]

Answer:

12 moles of cesium xenon heptafluoride

Explanation:

The reaction of cesium fluoride with xenon hexafluoride is CeF + XeF6 -> CeXeF7 and the reaction is balanced as written. So the mole ratio is 1:1:1. We are given 12 moles of CeF and 14 moles of XeF6 are reacting, but after the 12 moles of CeF react completely, the reaction will stop as we have run out of one of our reactants. So only 12 moles of CeXeF7 will be produced.

7 0

2 years ago

Which organism is responsible for clean up in this ecosystem?

Fynjy0 [20]

I would say that the organism that is responsible for clean up in this ecosystem are decomposers. They are organisms that break down dead or decaying organisms, and in doing so, they carry out the natural process of decomposition. Hope this answers the question.

6 0

2 years ago

Read 2 more answers

Calculate H3O+ when OH- is 2*10 -8

klio [65]

Relationship between [H3O+] and [OH-] is:

[H3O+] X [OH-] = 1.00 X10^-14

Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]

Just plug in and calculate your [H3O+] values

6 0

3 years ago