1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Semenov [28]
2 years ago
13

I need help with stoichiometry

Chemistry
1 answer:
shutvik [7]2 years ago
4 0
Um I don’t know what stoichiometry is. So I can’t help I am sorry wish I could
You might be interested in
How many moles of oxygen are there in 3 moles of Zn(NO3)2? (2 points)
muminat

there are 6 moles of oxygen in Zn(No3)2

4 0
2 years ago
You have a mass of 54 kg and are sitting on a stool. The normal force the stool applies on you is ...
Karo-lina-s [1.5K]

Answer:

529.2 N

Explanation:

As we have studied the first law of motion, which states that every action has some reaction, equal in magnitude but having an opposite direction.

The force that is acting on the student will be due to gravitational force, that is equal to his weight.

                                              F=mg: 54kg x 9.8m/s^2 =529.2 N

So the weight of student is exerting downwards towards the stool and land. The stool will also exert a force on the student that will be equal in magnitude but opposite in direction, then it will be 529.2 N.

This is because the student is sitting in a constant state and all the weight is exerted on the stool.

Note: This answer is very generic supposing that all the weight of the student is on stool. But, if we suppose that student's legs are on floor so it means the force of gravity acting on the stool has become less because student's mass on stool is less. So the answer would be a force somehow less than 529.2 N.  However, since the question asked normal force, it would be weight of student in general terms.

Hope it helps!

7 0
3 years ago
The orbital period of planet Venus is 0.62 years. What is its distance from the sun?
Vikki [24]

Kepler's third law shows the relationship between the orbital period of an object and the distance between the object and the object it orbits.

The simplified version of this law is: P^2 = a^3

Where,

P = period of the orbit in years = 0.62 years

a = average distance from the object to the object it orbits in AU. The astronomical unit AU is a unit of length which is roughly equivalent to the distance from Earth to the Sun.

Therefore calculating for a:

0.62 ^ 2 = a ^ 3

a = 0.62 ^ (2/3)

a = 0.727 AU = 0.72 AU

Therefore we can interpret this as: The distance from Venus to the Sun is about 72% of the distance from Earth to Sun.

<span>Answer: B. 0.72 AU</span>

5 0
3 years ago
What type of solid is candle wax
son4ous [18]

Hi Sara


I would say it is an amorphous solid.


Because it's gradually loses shape.


I hope that's help:)

8 0
3 years ago
Read 2 more answers
What does the atomic mass of a neutral atom tell you?
ExtremeBDS [4]

Answer:

yes

Explanation:

6 0
3 years ago
Other questions:
  • Calculate the mass of 3.5 mol C6H6
    10·1 answer
  • if you were going to invent a new way to power your mobile phone which type of electromatic waves wiuld be most useful to invist
    10·2 answers
  • What was the new theory that was developed of the continental drift?
    14·1 answer
  • Which of these salts is insoluble in water?
    8·1 answer
  • How many electrons are in polonium with a -3 charge?
    15·1 answer
  • Which solution reacts with LiOH(aq) to produce a salt and water?(1) KCl(aq) (2) CaO(aq) (3)NaOH(aq) (4)H2SO4(aq)
    5·1 answer
  • If a buffer contains 1.05M B and 0.750M BH+ has the pH of 9.5. What would be the pH after 0.005mol of HCL is added to 0.5L of so
    8·1 answer
  • Please help! I really need help on this!​
    7·1 answer
  • If C and Cl combined to make a compound, would it be covalent or ionic?
    15·1 answer
  • What is the definition of a chemical change that when two or more substances (molecules) combine to form a new substance (or new
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!