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astraxan [27]
3 years ago
8

A 30-kg girl and a 25-kg boy face each other on friction-free roller blades. the girl pushes the boy, who moves away at a speed

of 1.0 m/s. the girl's speed is
Chemistry
1 answer:
dsp733 years ago
6 0
0.83 m/s seems the correct answer, hope it helps
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Elements in group 17 have similar properties because they all have the name number of what
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Elements in group 17 have similar properties because they all the same number of electrons and valence electrons.

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True or false: <br> The following equation is balanced properly: 6CO2 + 6H2O → C6H12O6 + O2
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No as oxygen is not balance
In reactants side there is 12 oxygen and in the product side there is 8 oxygen
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Please help asap. will give brainliest to correct answer
Usimov [2.4K]
The answer is 232 plus 450
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How does the kinetic energy of solids liquids and gases compare?
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4 0
2 years ago
The half-life of a radioactive isotope is the amount of time it takes for a quantity of that isotope to decay to one half of its
Sedaia [141]

Radio active decay reactions follow first order rate kinetics.

a) The half life and decay constant for radio active decay reactions are related by the equation:

t_{\frac{1}{2}} =\frac{ln 2}{k}

t_{\frac{1}{2}} = \frac{0.693}{k}

Where k is the decay constant

b) Finding out the decay constant for the decay of C-14 isotope:

Decay constant (k) = \frac{0.693}{t_{\frac{1}{2}}}

k = \frac{0.693}{5230 years}

k = 1.325 * 10^{-4} yr^{-1}

c) Finding the age of the sample :

35 % of the radiocarbon is present currently.

The first order rate equation is,

[A] = [A_{0}]e^{-kt}

\frac{[A]}{[A_{0}]} = e^{-kt}

\frac{35}{100} = e^{-(1.325 *10^{-4})t}

ln(0.35) = -(1.325 *10^{-4})(t)

t = 7923 years

Therefore, age of the sample is 7923 years.

3 0
3 years ago
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