Answer:
1.48 × 10²⁴ atoms
Explanation:
Step 1: Calculate the moles of argon
Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.

Step 2: Calculate the atoms of argon
In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.

N2 + 3H2 -----> 2NH3
3 mol 2 mol
When 3 mol H2 react completely 2 mol NH3 are formed.
Answer:
100.8 °C
Explanation:
The Clausius-clapeyron equation is:
-Δ
Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'
Isolating for T2 gives:

(sorry for 'deltaHvap' I can not input symbols into equations)
thus T2=100.8 °C
Answer:
The elements in Group 1 (lithium, sodium, potassium, rubidium, cesium, and francium) are called the alkali metals. All of the alkali metals have a single s electron in their outermost principal energy. ... For example, the electron configuration of lithium (Li), the alkali metal of Period 2, is 1s22s1.
Answer:
Equal to 0.253 mol.
Explanation:
Hello,
In this case, since hydrogen and water are in a 2:2 molar relationship, the number of moles of hydrogen necessary to produce 0.253 mol of water will be also 0.253 mol as shown on the following stoichiometric factor:

Therefore, The number of moles of hydrogen that is needed to produce 0.253 mol of water is equal to 0.253 mol.
Best regards.