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elena55 [62]
3 years ago
9

How many atoms are in the mole of magnesium

Chemistry
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

6.02 × 10²³ atoms.

Explanation:

According to the Avogadro number, the one mole of any substance have 6.02 × 10²³ atoms.

The number 6.02 × 10²³ is called Avogadro number. it is the number of atoms, ions or molecules in one gram atoms of element, one gram ions of substance or one gram molecules of a compound.

For one mole of magnesium.

24.305 g of Mg = 1 mole of magnesium =  6.02 × 10²³ atoms of magnesium.

Other example includes:

18 g of water = one mole of water =  6.02 × 10²³ molecules of water.

23 g of sodium = one mole of sodium =  6.02 × 10²³ atoms of sodium.

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Read the given expression.
Jlenok [28]

Answer:

Choice number two. The value of "X" in this equation should be constant for all elements across a period.

Explanation:

Electrons are negative while protons are positive. Electrons are attracted to the proton but repel each other.

Consider an atom where electrons occupy more than one energy level. Consider the Bohr Model for that atom. Protons in the nucleus attract the electrons towards the center of the atom. However, at the same time, electrons in the inner shell will repel the valence electrons. That creates an outward force that pushes the valence electrons away from the atom.

The two forces mostly balance each other, but the attraction is slightly stronger. As a result, the overall force on the valence electrons is attractive. The effective nuclear charge gives the number of protons required to produce an attraction of that strength if there was no repulsion at all.

The value of effective nuclear charge is approximately the same as atomic number minus the number of inner-shell electrons. Apparently, the "X" in this question stands for the number of inner-shell electrons.

By the Aufbau Principle, all spots in the inner shell must be filled before more electrons can be added. Additionally, atoms in the same period have the same number of inner shells. As a result, the number of inner-shell electrons will be the same for all atoms in each period. Hence, the value of "X" should stay (approximately) the same across each period.

6 0
3 years ago
For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if hydrogen gas was removed from the reaction mixture? There will be a
Hoochie [10]
This uses something called <span>Le Chatelier's principle. It states essentially that any stress put upon a system will be corrected.

In more simple terms, it means that in an equilibrium, such as the equation N2(g) + 3H2(g) <=> 2NH3(g), removing a reactant will cause the system to create more of said reactant to compensate for its loss, or adding excess reactant will cause the system to remove some of the added reactant. For future reference, the same principle applies to products in an equilibrium as well. 

In this case, hydrogen gas is a reactant, and hydrogen is being removed. According to </span><span>Le Chatelier's principle, the system will shift to create more hydrogen gas. In essence, it will shift in the direction of the hydrogen gas, so there will be a shift toward the reactants.

To clear something up, Keq will not change, as it is a constant value with constant conditions (such as temperature, pressure, etc.).</span>
7 0
4 years ago
(-3,5); m= 2/3 plzzzzz help
AveGali [126]

Setting up the equation, you get

5=\frac{2}{3} *(-3)+b

b=7

Therefore, the equation is y=\frac{2}{3} x+7


6 0
3 years ago
Read 2 more answers
How much water would need to be added to 1092 mL of a 54.7 M NaCl solution to make a 0.25 M solution?
babunello [35]

Answer:

237.8L of water would need to be added.

Explanation:

The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).

Then figure out what information you have and what is being found. In this case:

M1 = 54.7 M

V1 = 1092 mL = 1.092 L

M2 = 0.25 M

V2 = unknown

Then solve the equation for whatever you are trying to find.

M1V1=M2V2

V2=M1V1/M2

Now you need to plug everything in.

V2=(54.7M*1.091L)/0.25M

V2=238.93L

That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.

238.93L - 1.091L = 237.8L

Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.

I hope this helps.  Let me know if anything is unclear.

8 0
3 years ago
6kg of coal (carbon) is burned in air. What mass of carbon dioxide will be produced? (Assume that combustion is complete and ign
Flauer [41]

The mass of carbon dioxide that would be produced will be 22 kg

<h3>Combustion of carbon</h3>

The combustion of carbon in air can be represented by the equation:

C + O2 ---> CO2

The mole ratio of C to O2 to CO2 is 1:1:1.

Mole of 6kg of carbon = mass/molar mass

                                      = 6000/12

                                      = 500 moles

Equivalent mole of CO2 produced = 500 moles

Mass of 500 moles CO2 = mole x molar mass

                                          = 500 x 44.01

                                           = 22,005 g or 22 kg approximately

More on combustion reactions can be found here: brainly.com/question/13649083

6 0
3 years ago
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