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Lady bird [3.3K]
3 years ago
7

Post-Lecture Assignment Chapter 06

Chemistry
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

Can you send an image of the question, please?

Explanation:

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Mechiancal weathering includes all of these except a.)ice b.)plants c.)animals d.)wind​
Nana76 [90]

The answer is D. Wind

Wind is considered physical weathering

7 0
4 years ago
If variable A decreases, how will variable B respond?
wel
Variable B will become lower due to variable A becoming smaller think of it like a seesaw if you put something on one side there will be a reaction on the other =)
7 0
4 years ago
Which chemical formula corresponds to this structural formula? c6h6h6h2 c14h6 c6h12 c6h14
Alexxandr [17]

The chemical formula C₂H₆O, which is designated as option D, is equivalent to this structural formula.

<h3><u>What is a Chemical Formula ?</u></h3>

Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus (+) and minus () signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.

  • An empirical formula represents by symbols, such as Na for sodium and Cl for chlorine, with subscripts that show the relative number of atoms in each.
  • The composition of any member of an entire class of compounds can be represented by a general formula, a sort of empirical formula.

To know more about Chemical formulas, refer to:

brainly.com/question/26388921

6 0
1 year ago
Read 2 more answers
If 100.0g of nitrogen is reacted with 100.0g of hydrogen, what is the excess reactant? What is the limiting reactant? Show your
Drupady [299]

N₂ : limiting reactant

H₂ : excess reactant

<h3>Further explanation</h3>

Given

mass of N₂ = 100 g

mass of H₂ = 100 g

Required

Limiting reactant

Excess reactant

Solution

Reaction

<em>N₂+3H₂⇒2NH₃</em>

mol N₂(MW=28 g/mol) :

\tt mol=\dfrac{mass}{MW}=\dfrac{100}{28}=3.571

mol H₂(MW= 2 g/mol) :

\tt mol=\dfrac{100}{2}=50

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

From the equation, mol ratio N₂ : H₂ = 1 : 3, so :

\tt \dfrac{3.571}{1}\div \dfrac{50}{3}=3.571\div 16.6

N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant

5 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
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