What is the empirical formula of a compound that is 40% sulfur and 60% oxygen by weight?
1 answer:
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Answer:
W = -262 J.
Explanation:
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In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:
So we plug in the given pressure and volumes to obtain:
Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:
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Answer:
r = 3.61x M/s
Explanation:
The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.
r = k.
K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :
x = 1
Now, to find the coefficient y let's do the same for the experiments 1 and 3:
y = 1
Now, we need to calculate the constant k in whatever experiment. Using the first :
k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]
Using the data given,
r =
r = 3.61x M/s