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Artemon [7]
4 years ago
14

Pressure in a hydraulic system is achieved by applying the force of gravity on a gas.

Physics
2 answers:
lana66690 [7]4 years ago
7 0
B) False.

The force of gravity is not used to create the hydraulic force.
-Dominant- [34]4 years ago
5 0
Your answer would be B. False. Due to in a hydraulic system, you can have pressure put on gas without gravity as well. Think of it like a shock absorber on a car, when you hit a bump in the road, the shock compresses, not due to gravity, but due to the weight of the car pushing down, while the wheel is pushing up. If anything, it would be closer to maybe, the law of inertia.
Hope this helps!
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A net force acting on a 5.0 kg box produces an acceleration of 4.2 m/s2. What acceleration, to the nearest tenth of a m/s2, will
SCORPION-xisa [38]

The acceleration that the net force will cause is 7.5 m/s²

To solve this problem, first, we need to find the net force.

⇒ Equation:

F = ma................ Equation 1

⇒ Where:

  • m = mass of the box
  • a = acceleration of the box

From the question,

⇒ Given;

  • m = 5.0 kg
  • a = 4.2 m/s²

⇒ Substitute these values into equation 1

  • F = 5×4.2
  • F = 21 N

We also use the same equation 1 to find the acceleration that the net force will cause to a box of mass 2.8 kg.

⇒ make a the subject in equation 1

  • a = F/m................. Equation 2

⇒ Substitute the appropriate values into equation 2

  • a = 21/2.8
  • a = 7.5 m/s²

Hence, The acceleration that the net force will cause is 7.5 m/s²

Learn more about acceleration here: brainly.com/question/605631

4 0
3 years ago
1)the magnetic field is strongest near_________of a bar magnet.
horrorfan [7]
1. Is A. at the poles because thats where the magnetic field is going out then coming back into the earth to produce the magnetic field.
2. Again its A. because the compass needle is attracted to " north " which is magnetic south. It does this because opposites attract.
3. This one would be B. Because if the magnets were being repelled the magnetic field lines would look like there was a line that the field hit and bounced off of it.
4. This answer is A. the magnetite helps them migrate so they know which way is north and which way is south.
5. This answer is A. Because without the domains there wouldn't be poles on the magnetic object. <span />
7 0
3 years ago
Read 2 more answers
Which is the force that results from use of a machine?
Goshia [24]

Answer:

D. Output force

Explanation:

The input force is the effort used to run the machine and this results in an output force.

3 0
2 years ago
How does friction affect basketball ad what is an example?
kaheart [24]
It affects basketball in a way called traction. The friction between the players' basketball shoes and the hard wooden floor is traction, or friction. Without it, players would slide everywhere and wouldn't be able to play the game.
5 0
4 years ago
A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of
Sunny_sXe [5.5K]

Answer:

5.8\; {\rm kg\cdot m \cdot s^{-1}}.

Explanation:

If the mass of an object is m and the velocity of that object is v, the linear momentum of that object would be m\, v.

Assume that the initial velocity of the mass is positive (6.0\; {\rm m\cdot s^{-1}}.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be (-4.0\; {\rm m\cdot s^{-1}}).

Thus, the change in the velocity of the mass would be:

\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

7 0
3 years ago
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