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3 years ago

I need help with geometry semester b on Edmentum anybody have answer keys ??

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

I do not have answer keys

Step-by-step explanation:

But i can be of greater help with your questions

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

What is the slop intercept form of a line that passes threw (4,-4) and (8, -10)

BigorU [14]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes, so we can find the slope:

$(x_ {1}, y_ {1}) :( 4, -4)\\(x_ {2}, y_ {2}) :( 8, -10)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-10 - (- 4)} {8-4} = \frac {-10+ 4} {4} = \frac {-6} {4} = - \frac {3} {2}$

Thus, the equation is of the form:

$y = - \frac {3} {2} x + b$

We substitute one of the points and find "b":

$-4 = - \frac {3} {2} (4) + b\\-4 = - \frac {12} {2} + b\\-4 + 6 = b\\b = 2$

Finally, the equation is of the form:

$y = - \frac {3} {2} +2$

ANswer:

$y = - \frac {3} {2} +2$

4 0

3 years ago

Please answer Ill give 5 stars to right answers: a neighbors dog barked at tana the last 4 out of 5 times she walked by their ho

oksian1 [2.3K]

Ratio of dog bark is 4:5

Multiply that by 20 each side

Ratio is now 80:100

So 80%

If they walk past 45 time you just have to multiply the ratio 4:5 by 9

36:45

So the dog would bark 36 times

6 0

2 years ago

A basketball player shoots a basketball that reaches a height above 15 feet before landing back on the ground exactly after 7 se

Papessa [141]

Answer:

I and IV

Step-by-step explanation:

Since the height of the basketball reaches above 15 feet, hence the maximum of the function should be greater than 15 feet. Also at 7 seconds, the ball is on the ground, hence f(7) = 0 feet

The maximum of a function is at x = -b/2a

i) f(x) = -(x-3)² + 16 = -(x² - 6x + 9) + 16 = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 16 = 16 > 15

Also f(7) = - (7 - 3)² + 16 = 0

Hence this option is correct

ii) f(x) = -x² + 8x - 7

The maximum of a function is at x = -b/2a = -8 / 2(-1) = 4

f(4) = -4² + 8(4) - 7 = 9 < 15 not correct

Also f(7) = - 7² + 8(7) - 7 = 0

Hence this option is not correct since the maximum f(4) = 9 < 15

iii) f(x) = -(x-3)² + 14 = -(x² - 6x + 9) + 14 = -x² + 6x + 5

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 14 = 14 < 15

Also f(7) = - (7 - 3)² + 14 = -2

Hence this option is not correct since the maximum f(4) = 9 < 15 and f(7) ≠ 0

iv)f(x) = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3)² + 6(3) + 7 = 16 > 15

Also f(7) = - (7)² + 6(7) + 7 = 0

Hence this option is correct

3 0

3 years ago

simplify the exponential expression completely. pleeeease help me!!!!! thank you so so so much!!! *will give brainliest*

Marrrta [24]

Answer:

( C ) p5 / q4

Step-by-step explanation:

8 0

3 years ago