<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
Answer:
Average speed is 60 km/hour
Explanation:
When we need to calculate average speed, we use this equation:
Where: 
position at the beginning
at the end
Then: 
Finally V = 60 km/hour
1). Work = (force) x (distance)
Work = (3,000 newtons) x (35 meters) = 105,000 newton-meters = <em>105,000 joules</em>
2). Power = (work) / (time)
Power = (105,000 joules) / (90 seconds)
= 1,166-2/3 joules per second =<em> 1,166 and 2/3 watts</em> .
<em>Note:</em>
That's no ordinary man.
1,166 watts is the same as roughly 1.6 horsepower.
Not too many people can sustain 1 horsepower or more for 90 seconds.
Answer:
Explanation:
Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.
In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.
Electric
field strength = Electric force/charge
E = F/q
E = (1.8×10^-1) / (6.4×10^-7)
E = 2.81×10^5 NC^-1
Hope it helped!
