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Eva8 [605]
3 years ago
8

A car travels from Boston to Hartford in 4 hours. The two cities are 240 kilometers apart. What was the average speed of the car

during the trip? A. 4 km/hour B. 960 km/hour C. 60 km/hour
Physics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

Average speed is 60 km/hour

Explanation:

When we need to calculate average speed, we use this equation:

V = \frac{x_{f} - x_{o}}{t_{f} - t_{o}}

Where:   x_{o} = 0 km   position at the beginning

              x_{f} = 240 km   at the end

              t_{o} = 0 hours

              t_{f} = 4 hours

Then:     V = \frac{240 km - 0 km}{4 hours - 0 hours}

              V = \frac{240 km}{4 hours}

Finally    V = 60 km/hour

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A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time
musickatia [10]

(x=yt-2)^2(56-tea)^2x10r

5 0
3 years ago
A 10 m long steel beam is accidentally dropped by a construction crane from a height of 4.89 m. The horizontal component of the
Otrada [13]

Answer:

e = 1.21 mV

Explanation:

given,                                

length of rod = 10 m                

height of drop = 4.89 m          

Earth’s magnetic field =  12.4 µT

acceleration of gravity = 9.8 m/s²

velocity of the beam                      

v = \sqrt{2gh}

v = \sqrt{2\times 9.8 \times 4.89}

v = 9.79 m/s                        

emf of the beam

e = B l v                              

e = 12.4 x 10⁻⁶ x 9.79 x 10

e = 1.21 x 10⁻³ V

e = 1.21 mV

4 0
3 years ago
Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area
Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

Explanation:

Given that,

Magnetic field = 42 μT

Area A=3.71\times10^{5}\ km^2

A=3.71\times10^{11}\ m^2

We need to calculate the flux per unit area

flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}

flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2

We need to calculate the total earth's surface area

A'=4\pi r^2

A'=4\times\pi\times(6.3781\times10^{6})^2

A'=5.1120\times10^{14}\ m^2

We need to calculate the rest of earth's area

A''=A-A'

Put the value into the formula

A''=5.1120\times10^{14}-3.71\times10^{11}

A''=5.10829\times10^{14}\ m^2

We need to calculate the net magnetic flux through the rest of Earth's surface

B'=5.10829\times10^{14}\times1.132\times10^{-16}

B'=5.782\times10^{-2}\ T

Hence, The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

3 0
4 years ago
I’m gym class you run 22m horizontal then climb a rope vertically for 4.8m. What is the direction angle of your total displaceme
Sliva [168]

The answer is: 12.30 degrees.

To solve this problem you must apply the proccedure shown below:

1. You run 22 meters horizontally and then you climb a rope vertically for 4.8 meters.

2. So. let's call the angle \alpha, therefore, you must find it using tan^{-1}, as following:

tan^{-1}(\alpha)=\frac{opposite}{adjacent} \\opposite=4.8\\adjacent=22

3. Substitute values and solve for the angle:

tan^{-1}(\alpha)=\frac{4.8}{22}\\\alpha=12.30degrees

5 0
3 years ago
Every thing is in the picture
vekshin1

Answer:

156

Explanation:

74+82=156

5 0
3 years ago
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