Circumference of the cylinder = 3.14 x 3.5 = 10.99 = 11 inches
so D. 11 x 14 is correct for the first part
area of the top = PI x r^2 = 3.14 x 1.75^2 = 9.62 inches
top and bottom = 9.62 x 2 = 19.23 = A. 19 inches
Answer:
n = 19/18
Step-by-step explanation:
Given:
11/6 = n + 7/9
Find n
11/6 = n + 7/9
Subtract 7/9 from both sides of the equation
11/6 - 7/9 = n + 7/9 - 7/9
11/6 - 7/9 = n
(99-42) / 54 = n
n = 57/54
n = 19/18
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
Yes you do and what grade are you in and do you need help answering these questions
A parabola is open up if a > 0.
The vertex formula:
(h; k) - the coordinates of the vertex
Therefore h = -5 < 0
Answer: B. y = x² + 10x + 24.
