as it is given that it covers a total distance 1 * 10^2 m
total time taken by it = 13.6 s
now the average speed is given as ratio of total distance and total time
so the average speed will be 7.35 m/s
now if it starts from rest and achieve the final speed as 7.35 m/s
now we can use kinematics
so its acceleration will be 3.68 m/s^2
Answer:
a) v(2) = 2m/s, v(3) = -2m/s
b) speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
c) 0 m/s
Explanation:
We can take the derivative of x(t) to find the equation of velocity
v(t) = x'(t) = 10 - 4t
(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s
v(3) = 10 - 4*3 = 10 - 12 = -2 m/s
(b) The speed would be the same as velocity without the direction
speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time