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3 years ago

Lucas plugs a lamp into the wall. The light bulb in the lamp turns on. What kind of energy transformation is this

2 answers:

7 0

A light bulb converts electric energy into heat and light energy, but it is different when you are using solar energy.Not that different though, the solar energy turns into electric energy that converts into heat and light energy.

pantera1 [17]3 years ago

5 0

Answer:

Electric energy from the outlet transforms to radiant energy and thermal energy in the lightbulb.

Explanation:

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A coal - fired power station produces 100MJ of electrical energy when it is supplied with 400MJ of energy from its fuel. The eff

Alexus [3.1K]

Answer:

100 divide by 400 times 100 percent

8 0

3 years ago

A college student is working on her physics homework in her dorm room. Her room contains a total of 6.0 x 10^26 gas molecules. A

IceJOKER [234]

Answer:

Temperature, T = 3.62 kelvin

Explanation:

It is given that,

Total number of gas molecules, $N=6\times 10^{26}$

Her body is converting chemical energy into thermal energy at a rate of 125 W, P = 125 W

Time taken, t = 6 min = 360 s

Energy of a gas molecules is given by :

$\Delta E =\dfrac{3}{2}NkT$

$T=\dfrac{2E}{3Nk}$ , k is Boltzmann constant

$T=\dfrac{2\times P\times t}{3Nk}$

$T=\dfrac{2\times 125\times 360}{3\times 6\times 10^{26}\times 1.38\times 10^{-23}}$

T = 3.62 K

So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.

4 0

3 years ago

Water flows over the edge of a waterfall at a rate of 1.2 x 10^6 kg/s. There are 50.0 m between the top and bottom of the waterf

Anit [1.1K]

Answer:

5.88×10⁸ W

Explanation:

Power = change in energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

4 0

3 years ago

Read 2 more answers

3. With a<br> you can measure just about anything.

Degger [83]

MULTIMETER combines the functions of ammeter, voltmeter and ohmmeter as a minimum.

5 0

3 years ago

A 5.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

Brut [27]

Answer:

75 N

Explanation:

In this problem, the position of the crate at time t is given by

$y(t)=2.80t+0.61t^3$

The velocity of the crate vs time is given by the derivative of the position, so it is:

$v(t)=y'(t)=\frac{d}{dt}(2.80t+0.61t^3)=2.80+1.83t^2$

Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:

$a(t)=v'(t)=\frac{d}{dt}(2.80+1.83t^2)=3.66t$ [m/s^2]

According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:

$F(t)=ma(t)$

where

m = 5.00 kg is the mass of the crate

At t = 4.10 s, the acceleration of the crate is

$a(4.10)=3.66\cdot 4.10 =15.0 m/s^2$

And therefore, the force on the crate is:

$F=ma=(5.00)(15.0)=75 N$

7 0

3 years ago